如何在Rust中分割string?
如何在Rust中分割一个string? 从它的文档中不清楚。 在Java中,我会这样做:
"some string 123 ffd".split("123");
使用split()
let mut split = "some string 123 ffd".split("123");
这给了一个迭代器,你可以循环,或collect()
到一个向量。
for s in split { println!("{}", s) } let vec = split.collect::<Vec<&str>>(); // OR let vec: Vec<&str> = split.collect();
有一个特殊的方法split
为结构String
:
fn split<'a, P>(&'a self, pat: P) -> Split<'a, P> where P: Pattern<'a>
按字符分割:
let v: Vec<&str> = "Mary had a little lamb".split(' ').collect(); assert_eq!(v, ["Mary", "had", "a", "little", "lamb"]);
按string拆分:
let v: Vec<&str> = "lion::tiger::leopard".split("::").collect(); assert_eq!(v, ["lion", "tiger", "leopard"]);
按closures分割:
let v: Vec<&str> = "abc1def2ghi".split(|c: char| c.is_numeric()).collect(); assert_eq!(v, ["abc", "def", "ghi"]);
有三个简单的方法:
-
分隔符 :
s.split("separator")
-
由空白 :
s.split_whitespace()
-
换行符 :
s.lines()
每种types的结果都是一个迭代器:
let text = "foo\r\nbar\n\nbaz\n"; let mut lines = text.lines(); assert_eq!(Some("foo"), lines.next()); assert_eq!(Some("bar"), lines.next()); assert_eq!(Some(""), lines.next()); assert_eq!(Some("baz"), lines.next()); assert_eq!(None, lines.next());
还有split_whitespace()
fn main() { let words: Vec<&str> = " foo bar\t\nbaz ".split_whitespace().collect(); println!("{:?}", words); // ["foo", "bar", "baz"] }