你如何确定哪些SQL表格有一个标识列编程
我想在SQL Server 2005中创build一列列，其中包含T-SQL中的标识列及其相应的表。
结果会是这样的：
TableName，ColumnName
SQL Server的另一种可能的方法是对系统表（可能会更改，版本之间）的依赖性较低，这是使用INFORMATION_SCHEMA视图：
select COLUMN_NAME, TABLE_NAME from INFORMATION_SCHEMA.COLUMNS where COLUMNPROPERTY(object_id(TABLE_SCHEMA+'.'+TABLE_NAME), COLUMN_NAME, 'IsIdentity') = 1 order by TABLE_NAME sys.columns.is_identity = 1
例如，
select o.name, c.name from sys.objects o inner join sys.columns c on o.object_id = c.object_id where c.is_identity = 1
另一种方式（2000/2005/2012/2014）：
IF ((SELECT OBJECTPROPERTY( OBJECT_ID(N'table_name_here'), 'TableHasIdentity')) = 1) PRINT 'Yes' ELSE PRINT 'No'
注意： table_name_here应该是schema.table ，除非架构是dbo 。
在SQL 2005中：
select object_name(object_id), name from sys.columns where is_identity = 1
这个查询似乎有诀窍：
SELECT sys.objects.name AS table_name, sys.columns.name AS column_name FROM sys.columns JOIN sys.objects ON sys.columns.object_id=sys.objects.object_id WHERE sys.columns.is_identity=1 AND sys.objects.type in (N'U')
这里是MSSQL 2000的工作版本。我修改了2005年的代码： http : //sqlfool.com/2011/01/identity-columns-are-you-nearing-the-limits/
/* Define how close we are to the value limit before we start throwing up the red flag. The higher the value, the closer to the limit. */ DECLARE @threshold DECIMAL(3,2); SET @threshold = .85; /* Create a temp table */ CREATE TABLE #identityStatus ( database_name VARCHAR(128) , table_name VARCHAR(128) , column_name VARCHAR(128) , data_type VARCHAR(128) , last_value BIGINT , max_value BIGINT ); DECLARE @dbname sysname; DECLARE @sql nvarchar(4000); -- Use an cursor to iterate through the databases since in 2000 there's no sp_MSForEachDB command... DECLARE c cursor FAST_FORWARD FOR SELECT name FROM master.dbo.sysdatabases WHERE name NOT IN('master', 'model', 'msdb', 'tempdb'); OPEN c; FETCH NEXT FROM c INTO @dbname; WHILE @@FETCH_STATUS = 0 BEGIN SET @sql = N'Use [' + @dbname + ']; Insert Into #identityStatus Select ''' + @dbname + ''' As [database_name] , Object_Name(id.id) As [table_name] , id.name As [column_name] , t.name As [data_type] , IDENT_CURRENT(Object_Name(id.id)) As [last_value] , Case When t.name = ''tinyint'' Then 255 When t.name = ''smallint'' Then 32767 When t.name = ''int'' Then 2147483647 When t.name = ''bigint'' Then 9223372036854775807 End As [max_value] From syscolumns As id Join systypes As t On id.xtype = t.xtype Where id.colstat&1 = 1 -- this identifies the identity columns (as far as I know) '; EXECUTE sp_executesql @sql; FETCH NEXT FROM c INTO @dbname; END CLOSE c; DEALLOCATE c; /* Retrieve our results and format it all prettily */ SELECT database_name , table_name , column_name , data_type , last_value , CASE WHEN last_value < 0 THEN 100 ELSE (1 - CAST(last_value AS FLOAT(4)) / max_value) * 100 END AS [percentLeft] , CASE WHEN CAST(last_value AS FLOAT(4)) / max_value >= @threshold THEN 'warning: approaching max limit' ELSE 'okay' END AS [id_status] FROM #identityStatus ORDER BY percentLeft; /* Clean up after ourselves */ DROP TABLE #identityStatus;
基于吉列尔莫答案的没有标识列表的列表：
SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE (TABLE_SCHEMA = 'dbo') AND (OBJECTPROPERTY(OBJECT_ID(TABLE_NAME), 'TableHasIdentity') = 0) ORDER BY TABLE_NAME
我认为这适用于SQL 2000：
SELECT CASE WHEN C.autoval IS NOT NULL THEN 'Identity' ELSE 'Not Identity' AND FROM sysobjects O INNER JOIN syscolumns C ON O.id = C.id WHERE O.NAME = @TableName AND C.NAME = @ColumnName
这对我使用Sql Server 2008的工作：
USE <database_name>; GO SELECT SCHEMA_NAME(schema_id) AS schema_name , t.name AS table_name , c.name AS column_name FROM sys.tables AS t JOIN sys.identity_columns c ON t.object_id = c.object_id ORDER BY schema_name, table_name; GO
用这个 ：
DECLARE @Table_Name VARCHAR(100) DECLARE @Column_Name VARCHAR(100) SET @Table_Name = '' SET @Column_Name = '' SELECT RowNumber = ROW_NUMBER() OVER ( PARTITION BY T.[Name] ORDER BY T.[Name], C.column_id ) , SCHEMA_NAME(T.schema_id) AS SchemaName , T.[Name] AS Table_Name , C.[Name] AS Field_Name , sysType.name , C.max_length , C.is_nullable , C.is_identity , C.scale , C.precision FROM Sys.Tables AS T LEFT JOIN Sys.Columns AS C ON ( T.[Object_Id] = C.[Object_Id] ) LEFT JOIN sys.types AS sysType ON ( C.user_type_id = sysType.user_type_id ) WHERE ( Type = 'U' ) AND ( C.Name LIKE '%' + @Column_Name + '%' ) AND ( T.Name LIKE '%' + @Table_Name + '%' ) ORDER BY T.[Name] , C.column_id
这适用于SQL Server 2005,2008和2012.我发现sys.identity_columns并不包含所有我的表与标识列。
SELECT a.name AS TableName, b.name AS IdentityColumn FROM sys.sysobjects a JOIN sys.syscolumns b ON a.id = b.id WHERE is_identity = 1 ORDER BY name;
查看文档页面，也可以使用状态栏。 你也可以添加四个部分标识符，它将在不同的服务器上工作。
SELECT a.name AS TableName, b.name AS IdentityColumn FROM [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.sysobjects a JOIN [YOUR_SERVER_NAME].[YOUR_DB_NAME].sys.syscolumns b ON a.id = b.id WHERE is_identity = 1 ORDER BY name;
来源： https ： //msdn.microsoft.com/en-us/library/ms186816.aspx
