NSString包含string崩溃

我试图根据其中的一个string字段来过滤数组。

nameLower和filterLower都有NSString的值，但我不断得到：

__NSCFString containsString:]: unrecognized selector sent to instance 0x7f876b79e160 -(void) filterFriendsArray:(NSString*)filter { [_filteredFriendsArray removeAllObjects]; for (FacebookUser* user in _friendsArray) { NSString* nameLower = [user.user.name lowercaseString]; NSString* filterLower = [filter lowercaseString]; if ([nameLower containsString:filterLower]) [_filteredFriendsArray addObject:user]; } _displayedFriendsArray = _filteredFriendsArray; } 

Answer 1

如果你想要你的代码在iOS 7和iOS 8上工作，你应该使用rangeOfString调用中的一个来代替。 基本上如果返回的范围长度为零，子string不在那里。

 /* These methods return length==0 if the target string is not found. So, to check for containment: ([str rangeOfString:@"target"].length > 0). Note that the length of the range returned by these methods might be different than the length of the target string, due composed characters and such. */ - (NSRange)rangeOfString:(NSString *)aString; - (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask; - (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask range:(NSRange)searchRange; - (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask range:(NSRange)searchRange locale:(NSLocale *)locale NS_AVAILABLE(10_5, 2_0); 

显然，使用rangeOfString自己实现containsString是很简单的：

 @implementation NSString (Contains) - (BOOL)myContainsString:(NSString*)other { NSRange range = [self rangeOfString:other]; return range.length != 0; } @end 

Answer 2

将rangeOfString与NSNotFound进行比较

 NSRange range = [self rangeOfString:other]; if(range.location != NSNotFound){ //do something } 

Answer 3

使用以下：

 if (![[NSString class] respondsToSelector:@selector(containsString)]) { //ios 7 NSRange range = [mystring rangeOfString:other]; if(range.location != NSNotFound){ //do something } } else //for iOS 8 { if ([mystring containsString: other]) { //do something } } 

Answer 4

对于那些在XLForm中遇到过这种情况的人 ，请确保在使用pod安装XLForm时

 platform :ios, '7' pod 'XLForm' 

它已经被固定在3.1

从

 if ([cellClassString contains:@"/"]) { } 

至

 if ([cellClassString rangeOfString:@"/"].location != NSNotFound) { } 

Answer 5

我将我的解决scheme封装在YJKit中，并且即使对于iOS 8以下的旧版本，也可以调用 – [NSString containsString：]。

 bool _yj_streq(const char *str1, const char *str2, size_t length) { for (int i = 0; i < length; i++) { if (*str1++ != *str2++) { return false; } } return true; } - (BOOL)yj_containsString:(NSString *)string { NSAssert(string != nil, @"*** -[%@ containsString:] can not use nil argument.", [self class]); size_t len1 = (size_t)self.length; size_t len2 = (size_t)string.length; if (len1 == 0 || len2 == 0 || len1 < len2) { return NO; } const char *str1 = self.UTF8String; const char *str2 = string.UTF8String; for (size_t i = 0; i <= len1 - len2; i++) { const char *substr1 = str1 + i; if (_yj_streq(substr1, str2, len2)) { return YES; } else { continue; } } return NO; } 

这里是我的源代码： https : //github.com/huang-kun/YJKit/blob/master/YJKit/Base/Foundation/Categories/Generics/NSString%2BYJCompatible.m

Answer 6

由w0mbat给出的答案的快速版本：

 extension NSString { func compatibleContainsString(string: NSString) -> Bool{ let range = self.rangeOfString(string as String) return range.length != 0 } }