从date范围中生成date
我想运行一个查询
select ... as days where `date` is between '2010-01-20' and '2010-01-24' 并返回如下数据：
天 ---------- 2010-01-20 2010-01-21 2010-01-22 2010-01-23 2010-01-24
此解决scheme不使用循环，过程或临时表 。 子查询会生成最近一千天的date，并且可以按照您的意愿延伸到前后。
select a.Date from ( select curdate() - INTERVAL (aa + (10 * ba) + (100 * ca)) DAY as Date from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c ) a where a.Date between '2010-01-20' and '2010-01-24'
输出：
Date ---------- 2010-01-24 2010-01-23 2010-01-22 2010-01-21 2010-01-20
性能注意事项
在这里testing一下 ，性能出奇的好： 上面的查询需要0.0009秒。
如果我们扩展子查询来生成约。 100,000个数字（因此约274年的date），它运行在0.0458秒。
顺便说一句，这是一个非常便携的技术，与大多数数据库一起工作，只需稍作调整。
返回1000天的SQL小提琴示例
这是使用视图的另一个变体：
CREATE VIEW digits AS SELECT 0 AS digit UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9; CREATE VIEW numbers AS SELECT ones.digit + tens.digit * 10 + hundreds.digit * 100 + thousands.digit * 1000 AS number FROM digits as ones, digits as tens, digits as hundreds, digits as thousands; CREATE VIEW dates AS SELECT SUBDATE(CURRENT_DATE(), number) AS date FROM numbers;
然后，你可以简单地做（看看它是多么优雅？）：
SELECT date FROM dates WHERE date BETWEEN '2010-01-20' AND '2010-01-24' ORDER BY date
更新
值得注意的是，您只能从当前date开始生成过去的date 。 如果你想生成任何types的date范围（过去，未来，和之间），你将不得不使用这个视图：
CREATE VIEW dates AS SELECT SUBDATE(CURRENT_DATE(), number) AS date FROM numbers UNION ALL SELECT ADDDATE(CURRENT_DATE(), number + 1) AS date FROM numbers;
接受的答案不适用于PostgreSQL（在“a”或附近的语法错误）。
在PostgreSQL中这样做的方式是使用generate_series函数，即：
SELECT day::date FROM generate_series('2010-01-20', '2010-01-24', INTERVAL '1 day') day; day ------------ 2010-01-20 2010-01-21 2010-01-22 2010-01-23 2010-01-24 (5 rows)
使用recursion通用expression式（CTE），您可以生成date列表，然后从中进行select。 显然，你通常不想创build300万个date，所以这只是说明了可能性。 您可以简单地限制CTE内的date范围，并使用CTE省略select语句中的where子句。
with [dates] as ( select convert(datetime, '1753-01-01') as [date] --start union all select dateadd(day, 1, [date]) from [dates] where [date] < '9999-12-31' --end ) select [date] from [dates] where [date] between '2013-01-01' and '2013-12-31' option (maxrecursion 0)
在Microsoft SQL Server 2005上，生成所有可能date的CTE列表1:08。 生成一百年不到一秒钟。
没有循环/游标的旧式解决scheme是创build一个NUMBERS表，该表有一个Integer列，其值从1开始。
CREATE TABLE `example`.`numbers` ( `id` int(10) unsigned NOT NULL auto_increment, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1;
您需要填充足够的logging以满足您的需求：
INSERT INTO NUMBERS (id) VALUES (NULL);
一旦你有NUMBERS表，你可以使用：
SELECT x.start_date + INTERVAL n.id-1 DAY FROM NUMBERS n JOIN (SELECT STR_TO_DATE('2010-01-20', '%Y-%m-%d') AS start_date FROM DUAL) x WHERE x.start_date + INTERVAL n.id-1 DAY <= '2010-01-24'
绝对的低技术解决scheme将是：
SELECT STR_TO_DATE('2010-01-20', '%Y-%m-%d') FROM DUAL UNION ALL SELECT STR_TO_DATE('2010-01-21', '%Y-%m-%d') FROM DUAL UNION ALL SELECT STR_TO_DATE('2010-01-22', '%Y-%m-%d') FROM DUAL UNION ALL SELECT STR_TO_DATE('2010-01-23', '%Y-%m-%d') FROM DUAL UNION ALL SELECT STR_TO_DATE('2010-01-24', '%Y-%m-%d') FROM DUAL
你会用它做什么？
生成date或数字列表以便左键join。 你会这样做，以便查看数据中有什么空白，因为你是左连接到一个序列数据列表 – 空值将使它明显的地方存在差距。
MSSQL查询
select datetable.Date from ( select DATEADD(day,-(aa + (10 * ba) + (100 * ca)),getdate()) AS Date from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c ) datetable where datetable.Date between '2014-01-20' and '2014-01-24' order by datetable.Date DESC
产量
Date ----- 2014-01-23 12:35:25.250 2014-01-22 12:35:25.250 2014-01-21 12:35:25.250 2014-01-20 12:35:25.250
对于Access 2010 – 需要多个步骤; 我遵循上面发布的相同模式，但认为我可以帮助Access中的某个人。 为我工作很好，我不必保留一个种子的date表。
创build一个名为DUAL的表（类似于Oracle DUAL表的工作方式）
- ID（自动编号）
- DummyColumn（文本）
- 添加一行值（1，“DummyRow”）
创build一个名为“ZeroThru9Q”的查询; 手动input以下语法：
SELECT 0 AS a FROM dual UNION ALL SELECT 1 FROM dual UNION ALL SELECT 2 FROM dual UNION ALL SELECT 3 FROM dual UNION ALL SELECT 4 FROM dual UNION ALL SELECT 5 FROM dual UNION ALL SELECT 6 FROM dual UNION ALL SELECT 7 FROM dual UNION ALL SELECT 8 FROM dual UNION ALL SELECT 9 FROM dual;
创build一个名为“TodayMinus1KQ”的查询（用于今天之前的date）; 手动input以下语法：
SELECT date() - (aa + (10 * ba) + (100 * ca)) AS MyDate FROM (SELECT * FROM ZeroThru9Q) AS a, (SELECT * FROM ZeroThru9Q) AS b, (SELECT * FROM ZeroThru9Q) AS c
创build一个名为“TodayPlus1KQ”的查询（用于今天之后的date）; 手动input以下语法：
SELECT date() + (aa + (10 * ba) + (100 * ca)) AS MyDate FROM (SELECT * FROM ZeroThru9Q) AS a, (SELECT * FROM ZeroThru9Q) AS b, (SELECT * FROM ZeroThru9Q) AS c;
创build名为“TodayPlusMinus1KQ”的联合查询（date为+/- 1000天）：
SELECT MyDate FROM TodayMinus1KQ UNION SELECT MyDate FROM TodayPlus1KQ;
现在你可以使用查询：
SELECT MyDate FROM TodayPlusMinus1KQ WHERE MyDate BETWEEN #05/01/2014# and #05/30/2014#
thx奔腾10 – 你让我joinstackoverflow 🙂 – 这是我的移植到msaccess – 认为它可以在任何版本的工作：
SELECT date_value FROM (SELECT a.espr1+(10*b.espr1)+(100*c.espr1) AS integer_value, dateadd("d",integer_value,dateserial([start_year], [start_month], [start_day])) as date_value FROM (select * from ( select top 1 "0" as espr1 from MSysObjects union all select top 1 "1" as espr2 from MSysObjects union all select top 1 "2" as espr3 from MSysObjects union all select top 1 "3" as espr4 from MSysObjects union all select top 1 "4" as espr5 from MSysObjects union all select top 1 "5" as espr6 from MSysObjects union all select top 1 "6" as espr7 from MSysObjects union all select top 1 "7" as espr8 from MSysObjects union all select top 1 "8" as espr9 from MSysObjects union all select top 1 "9" as espr9 from MSysObjects ) as a, ( select top 1 "0" as espr1 from MSysObjects union all select top 1 "1" as espr2 from MSysObjects union all select top 1 "2" as espr3 from MSysObjects union all select top 1 "3" as espr4 from MSysObjects union all select top 1 "4" as espr5 from MSysObjects union all select top 1 "5" as espr6 from MSysObjects union all select top 1 "6" as espr7 from MSysObjects union all select top 1 "7" as espr8 from MSysObjects union all select top 1 "8" as espr9 from MSysObjects union all select top 1 "9" as espr9 from MSysObjects ) as b, ( select top 1 "0" as espr1 from MSysObjects union all select top 1 "1" as espr2 from MSysObjects union all select top 1 "2" as espr3 from MSysObjects union all select top 1 "3" as espr4 from MSysObjects union all select top 1 "4" as espr5 from MSysObjects union all select top 1 "5" as espr6 from MSysObjects union all select top 1 "6" as espr7 from MSysObjects union all select top 1 "7" as espr8 from MSysObjects union all select top 1 "8" as espr9 from MSysObjects union all select top 1 "9" as espr9 from MSysObjects ) as c ) as d) WHERE date_value between dateserial([start_year], [start_month], [start_day]) and dateserial([end_year], [end_month], [end_day]);
引用MSysObjects只是因为访问需要一个表countin'至less有一条logging，在一个from子句 – 任何至less有一个logging的表会做。
如果你将需要更多的几天，你需要一张桌子。
在mysql中创build一个date范围
然后，
select from days.day, count(mytable.field) as fields from days left join mytable on day=date where date between x and y;
程序+临时表：
DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `days`(IN dateStart DATE, IN dateEnd DATE) BEGIN CREATE TEMPORARY TABLE IF NOT EXISTS date_range (day DATE); WHILE dateStart <= dateEnd DO INSERT INTO date_range VALUES (dateStart); SET dateStart = DATE_ADD(dateStart, INTERVAL 1 DAY); END WHILE; SELECT * FROM date_range; DROP TEMPORARY TABLE IF EXISTS date_range; END
比被接受的答案更短，同样的想法：
(SELECT TRIM('2016-01-05' + INTERVAL a + b DAY) date FROM (SELECT 0 a UNION SELECT 1 a UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) d, (SELECT 0 b UNION SELECT 10 UNION SELECT 20 UNION SELECT 30 UNION SELECT 40) m WHERE '2016-01-05' + INTERVAL a + b DAY <= '2016-01-21')
尝试这个。
SELECT TO_DATE('20160210','yyyymmdd') - 1 + LEVEL AS start_day from DUAL connect by level <= (TO_DATE('20160228','yyyymmdd') + 1) - TO_DATE('20160210','yyyymmdd') ;
好吧..试试这个： http : //www.devshed.com/c/a/MySQL/Delving-Deeper-into-MySQL-50/
http://dev.mysql.com/doc/refman/5.0/en/loop-statement.html
http://www.roseindia.net/sql/mysql-example/mysql-loop.shtml
用它来生成临时表，然后在临时表上执行select *操作。 或者一次输出一个结果。
你说你想做的事情不能用SELECT语句来完成 ，但是它可能适用于特定于MySQL的事情。
然后再次，也许你需要游标： http : //dev.mysql.com/doc/refman/5.0/en/cursors.html
对于Oracle，我的解决scheme是：
select trunc(sysdate-dayincrement, 'DD') from dual, (select level as dayincrement from dual connect by level <= 30)
系统date可以更改为特定的date和级别号码可以更改以提供更多的date。
正如已经提到的许多精彩的答案所说的（或者至less是暗示的），一旦你有一组数字来处理这个问题就很容易解决。
注意：以下是T-SQL，但这仅仅是我在这里和在networking上已经提到的一般概念的具体实现。 将代码转换为您select的方言应该相对简单。
怎么样？ 考虑这个查询：
SELECT DATEADD(d, N, '0001-01-22') FROM Numbers -- A table containing the numbers 0 through N WHERE N <= 5;
以上产生date范围1/22/0001 – 1/27/0001，是非常平凡的。 上述查询中有2个关键信息： 开始date 0001-01-22 ， 偏移量 5 。 如果我们结合这两个信息，那么我们显然有我们的结束date。 因此，给定两个date，产生一个范围可以被分解如下：
-
find两个给定date（偏移量）之间的差异，轻松：
-- Returns 125 SELECT ABS(DATEDIFF(d, '2014-08-22', '2014-12-25'))这里使用
ABS()确保date顺序不相关。 -
生成一个有限的数字，也很容易：
-- Returns the numbers 0-2 SELECT N = ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) - 1 FROM(SELECT 'A' AS S UNION ALL SELECT 'A' UNION ALL SELECT 'A')注意我们并不关心我们
FROM这里select什么。 我们只需要一个集合来处理，以便计算它的行数。 我个人使用TVF，有的使用CTE，有的使用数字表，而是使用了。 我主张使用您也了解的性能最高的解决scheme。
结合这两种方法将解决我们的问题：
DECLARE @date1 DATE = '9001-11-21'; DECLARE @date2 DATE = '9001-11-23'; SELECT D = DATEADD(d, N, @date1) FROM ( SELECT N = ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) - 1 FROM (SELECT 'A' AS S UNION ALL SELECT 'A' UNION ALL SELECT 'A') S ) Numbers WHERE N <= ABS(DATEDIFF(d, @date1, @date2));
上面的例子是可怕的代码，但是演示了一切如何。
更多乐趣
我需要做很多这样的事情，所以我把逻辑封装在两个TVF中。 第一个生成一个数字范围，第二个使用这个function来生成一个date范围。 math是确保input顺序无关紧要，因为我想使用GenerateRangeSmallInt可用的全部数字。
以下函数需要16ms的CPU时间才能返回65536个date的最大范围。
CREATE FUNCTION dbo.GenerateRangeDate ( @date1 DATE, @date2 DATE ) RETURNS TABLE WITH SCHEMABINDING AS RETURN ( SELECT D = DATEADD(d, N + 32768, CASE WHEN @date1 <= @date2 THEN @date1 ELSE @date2 END) FROM dbo.GenerateRangeSmallInt(-32768, ABS(DATEDIFF(d, @date1, @date2)) - 32768) ); GO CREATE FUNCTION dbo.GenerateRangeSmallInt ( @num1 SMALLINT = -32768 , @num2 SMALLINT = 32767 ) RETURNS TABLE WITH SCHEMABINDING AS RETURN ( WITH Numbers(N) AS ( SELECT N FROM(VALUES (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 16 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 32 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 48 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 64 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 80 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 96 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 112 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 128 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 144 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 160 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 176 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 192 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 208 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 224 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 240 , (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 256 ) V (N) ) SELECT TOP(ABS(CAST(@num1 AS INT) - CAST(@num2 AS INT)) + 1) N = ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) + CASE WHEN @num1 <= @num2 THEN @num1 ELSE @num2 END - 1 FROM Numbers A , Numbers B );
如果你想要两个date之间的date列表：
create table #dates ([date] smalldatetime) while @since < @to begin insert into #dates(dateadd(day,1,@since)) set @since = dateadd(day,1,@since) end select [date] from #dates
*小提琴在这里： http ://sqlfiddle.com/#!6/9eecb/ 3469
在两个date字段之间生成date
如果你知道SQL CTE查询，那么这个解决scheme将帮助你解决你的问题
这里是例子
我们有一张桌子的date
表名称：“testdate”
STARTDATE ENDDATE 10/24/2012 10/24/2012 10/27/2012 10/29/2012 10/30/2012 10/30/2012
要求结果：
STARTDATE 10/24/2012 10/27/2012 10/28/2012 10/29/2012 10/30/2012
解：
WITH CTE AS (SELECT DISTINCT convert(varchar(10),StartTime, 101) AS StartTime, datediff(dd,StartTime, endTime) AS diff FROM dbo.testdate UNION ALL SELECT StartTime, diff - 1 AS diff FROM CTE WHERE diff<> 0) SELECT DISTINCT DateAdd(dd,diff, StartTime) AS StartTime FROM CTE
说明：CTErecursion查询说明
-
查询的第一部分：
SELECT DISTINCT convert(varchar(10), StartTime, 101) AS StartTime, datediff(dd, StartTime, endTime) AS diff FROM dbo.testdate说明：firstcolumn是“startdate”，第二列是开始date和结束date的差异，将被视为“差异”列
-
查询的第二部分：
UNION ALL SELECT StartTime, diff-1 AS diff FROM CTE WHERE diff<>0说明：Union all将inheritance上述查询的结果，直到结果变为null，所以“StartTime”结果是从生成的CTE查询inheritance的，并且从diff减去-1，所以它看起来像3,2和1，直到0
例如
STARTDATE DIFF 10/24/2012 0 10/27/2012 0 10/27/2012 1 10/27/2012 2 10/30/2012 0
结果规范
STARTDATE Specification 10/24/2012 --> From Record 1 10/27/2012 --> From Record 2 10/27/2012 --> From Record 2 10/27/2012 --> From Record 2 10/30/2012 --> From Record 3
-
查询的第三部分
SELECT DISTINCT DateAdd(dd,diff, StartTime) AS StartTime FROM CTE它会在“startdate”中添加一天的“diff”，所以结果应该如下
结果
STARTDATE 10/24/2012 10/27/2012 10/28/2012 10/29/2012 10/30/2012
set language 'SPANISH' DECLARE @table table(fechaDesde datetime , fechaHasta datetime ) INSERT @table VALUES('20151231' , '20161231'); WITH x AS ( SELECT DATEADD( m , 1 ,fechaDesde ) as fecha FROM @table UNION ALL SELECT DATEADD( m , 1 ,fecha ) FROM @table t INNER JOIN x ON DATEADD( m , 1 ,x.fecha ) <= t.fechaHasta ) SELECT LEFT( CONVERT( VARCHAR, fecha , 112 ) , 6 ) as Periodo_Id ,DATEPART ( dd, DATEADD(dd,-(DAY(fecha)-1),fecha)) Num_Dia_Inicio ,DATEADD(dd,-(DAY(fecha)-1),fecha) Fecha_Inicio ,DATEPART ( mm , fecha ) Mes_Id ,DATEPART ( yy , fecha ) Anio ,DATEPART ( dd, DATEADD(dd,-(DAY(DATEADD(mm,1,fecha))),DATEADD(mm,1,fecha))) Num_Dia_Fin ,DATEADD(dd,-(DAY(DATEADD(mm,1,fecha))),DATEADD(mm,1,fecha)) ultimoDia ,datename(MONTH, fecha) mes ,'Q' + convert(varchar(10), DATEPART(QUARTER, fecha)) Trimestre_Name FROM x OPTION(MAXRECURSION 0)
DELIMITER $$ CREATE PROCEDURE GenerateRangeDates(IN dateStart DATE, IN dateEnd DATE) BEGIN CREATE TEMPORARY TABLE IF NOT EXISTS dates (day DATE); loopDate: LOOP INSERT INTO dates(day) VALUES (dateStart); SET dateStart = DATE_ADD(dateStart, INTERVAL 1 DAY); IF dateStart <= dateEnd THEN ITERATE loopDate; ELSE LEAVE loopDate; END IF; END LOOP loopDate; SELECT day FROM dates; DROP TEMPORARY TABLE IF EXISTS dates; END $$ -- Call procedure call GenerateRangeDates( now() - INTERVAL 40 DAY, now() );
SQLite版本的RedFilters顶级解决scheme
select d.Date from ( select date(julianday('2010-01-20') + (aa + (10 * ba) + (100 * ca))) as Date from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c ) d where d.Date between '2010-01-20' and '2010-01-24' order by d.Date
改进工作日join自定义假期表 microsoft MSSQL 2012 for powerpivotdate表https://gist.github.com/josy1024/cb1487d66d9e0ccbd420bc4a23b6e90e
with [dates] as ( select convert(datetime, '2016-01-01') as [date] --start union all select dateadd(day, 1, [date]) from [dates] where [date] < '2018-01-01' --end ) select [date] , DATEPART (dw,[date]) as Wochentag , (select holidayname from holidaytable where holidaytable.hdate = [date]) as Feiertag from [dates] where [date] between '2016-01-01' and '2016-31-12' option (maxrecursion 0)
对于任何想要这个作为保存视图的人（MySQL不支持在视图中嵌套的select语句）：
create view zero_to_nine as select 0 as n union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9; create view date_range as select curdate() - INTERVAL (an + (10 * bn) + (100 * cn)) DAY as date from zero_to_nine as a cross join zero_to_nine as b cross join zero_to_nine as c;
你可以这样做
select * from date_range
要得到
date --- 2017-06-06 2017-06-05 2017-06-04 2017-06-03 2017-06-02 ...
在飞行中生成这些date是一个好主意。 不过，我觉得自己并不舒服，所以我最终select了以下解决scheme：
- 创build了一个表格“DatesNumbers”，它将包含用于date计算的数字：
CREATE TABLE DatesNumbers ( i MEDIUMINT NOT NULL, PRIMARY KEY (i) ) COMMENT='Used by Dates view' ;
- 使用上述技术填充表格，数字从-59999到40000.这个范围将使我的date从59999天（〜164年）到40000天（109年）
INSERT INTO DatesNumbers SELECT ai + (10 * bi) + (100 * ci) + (1000 * di) + (10000 * ei) - 59999 AS i FROM (SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a , (SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b , (SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c , (SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS d , (SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e ;
- 创build一个视图“date”：
SELECT i , CURRENT_DATE() + INTERVAL i DAY AS Date FROM DatesNumbers
而已。
- （+）易于阅读的查询
- （+）没有在飞行数字世代
- （+）提供过去和未来的date，因此在这个post中没有任何联盟。
- （+）“过去只有”或“将来只有”date可以使用
WHERE i < 0或WHERE i > 0（PK） - （ – ）使用“临时”表和视图
