如何发送电子邮件附件？

我在理解如何使用Python向附件发送电子邮件时遇到问题。 我已经成功通过smtplib发送了简单的邮件。 有人可以解释如何发送电子邮件中的附件。 我知道在网上有其他的post，但作为一个Python初学者，我发现他们很难理解。

Answer 1

这是另一个，从这里改编：

 import smtplib from os.path import basename from email.mime.application import MIMEApplication from email.mime.multipart import MIMEMultipart from email.mime.text import MIMEText from email.utils import COMMASPACE, formatdate def send_mail(send_from, send_to, subject, text, files=None, server="127.0.0.1"): assert isinstance(send_to, list) msg = MIMEMultipart() msg['From'] = send_from msg['To'] = COMMASPACE.join(send_to) msg['Date'] = formatdate(localtime=True) msg['Subject'] = subject msg.attach(MIMEText(text)) for f in files or []: with open(f, "rb") as fil: part = MIMEApplication( fil.read(), Name=basename(f) ) # After the file is closed part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f) msg.attach(part) smtp = smtplib.SMTP(server) smtp.sendmail(send_from, send_to, msg.as_string()) smtp.close() 

这和第一个例子差不多，但是应该更容易一些。

Answer 2

这是我最终使用的代码：

 import smtplib from email.MIMEMultipart import MIMEMultipart from email.MIMEBase import MIMEBase from email import Encoders SUBJECT = "Email Data" msg = MIMEMultipart() msg['Subject'] = SUBJECT msg['From'] = self.EMAIL_FROM msg['To'] = ', '.join(self.EMAIL_TO) part = MIMEBase('application', "octet-stream") part.set_payload(open("text.txt", "rb").read()) Encoders.encode_base64(part) part.add_header('Content-Disposition', 'attachment; filename="text.txt"') msg.attach(part) server = smtplib.SMTP(self.EMAIL_SERVER) server.sendmail(self.EMAIL_FROM, self.EMAIL_TO, msg.as_string()) 

代码和Oli的文章非常相似。 谢谢大家

基于二进制文件电子邮件附件问题post的代码。

Answer 3

这里是Oli for python 3的修改版本

 import smtplib, os from email.mime.multipart import MIMEMultipart from email.mime.base import MIMEBase from email.mime.text import MIMEText from email.utils import COMMASPACE, formatdate from email import encoders def send_mail( send_from, send_to, subject, text, files=[], server="localhost", port=587, username='', password='', isTls=True): msg = MIMEMultipart() msg['From'] = send_from msg['To'] = COMMASPACE.join(send_to) msg['Date'] = formatdate(localtime = True) msg['Subject'] = subject msg.attach( MIMEText(text) ) for f in files: part = MIMEBase('application', "octet-stream") part.set_payload( open(f,"rb").read() ) encoders.encode_base64(part) part.add_header('Content-Disposition', 'attachment; filename="{0}"'.format(os.path.basename(f))) msg.attach(part) smtp = smtplib.SMTP(server, port) if isTls: smtp.starttls() smtp.login(username,password) smtp.sendmail(send_from, send_to, msg.as_string()) smtp.quit() 

Answer 4

 from email.MIMEMultipart import MIMEMultipart from email.MIMEText import MIMEText from email.MIMEImage import MIMEImage import smtplib msg = MIMEMultipart() msg.attach(MIMEText(file("text.txt").read())) msg.attach(MIMEImage(file("image.png").read())) # to send mailer = smtplib.SMTP() mailer.connect() mailer.sendmail(from_, to, msg.as_string()) mailer.close() 

改编自这里 。

Answer 5

我能得到的最简单的代码是：

 #for attachment email from django.core.mail import EmailMessage def attachment_email(request): email = EmailMessage( 'Hello', #subject 'Body goes here', #body '[e-mail]', #from ['[e-mail]'], #to ['[e-mail]'], #bcc reply_to=['[e-mail]'], headers={'Message-ID': 'foo'}, ) email.attach_file('/my/path/file') email.send() 

它基于官方的Django文档