用另一个数据更新一个表
表格1:
id name desc ----------------------- 1 a abc 2 b def 3 c adf
表2:
id name desc ----------------------- 1 x 123 2 y 345
如何运行一个SQL更新查询,可以使用相同的ID更新表1与表2的名称和desc? 所以我得到的最终结果是
表格1:
id name desc ----------------------- 1 x 123 2 y 345 3 c adf
如何做到这一点:
- SQL Server
- MySQL的
- PostgreSQL的
- 神谕
对于MySql:
UPDATE table1 JOIN table2 ON table1.id = table2.id SET table1.name = table2.name, table1.`desc` = table2.`desc`
对于Sql Server:
UPDATE table1 SET table1.name = table2.name, table1.[desc] = table2.[desc] FROM table1 JOIN table2 ON table1.id = table2.id
Oracle 11g R2:
create table table1 ( id number, name varchar2(10), desc_ varchar2(10) ); create table table2 ( id number, name varchar2(10), desc_ varchar2(10) ); insert into table1 values(1, 'a', 'abc'); insert into table1 values(2, 'b', 'def'); insert into table1 values(3, 'c', 'ghi'); insert into table2 values(1, 'x', '123'); insert into table2 values(2, 'y', '456'); merge into table1 t1 using (select * from table2) t2 on (t1.id = t2.id) when matched then update set t1.name = t2.name, t1.desc_ = t2.desc_; select * from table1; ID NAME DESC_ ---------- ---------- ---------- 1 x 123 2 y 456 3 c ghi
另请参阅Oracle – 使用内部联接更新语句 。
尝试下面的代码。 它正在为我工作….
UPDATE TableOne SET field1 =(SELECT TableTwo.field1 FROM TableTwo WHERE TableOne.id=TableTwo.id), field2 =(SELECT TableTwo.field2 FROM TableTwo WHERE TableOne.id=TableTwo.id) WHERE TableOne.id = (SELECT TableTwo.id FROM TableTwo WHERE TableOne.id = TableTwo.id)
UPDATE table1 SET `ID` = (SELECT table2.id FROM table2 WHERE table1.`name`=table2.`name`)
使用以下查询块根据ID更新Table1与Table2:
UPDATE Table1, Table2 SET Table1.DataColumn= Table2.DataColumn where Table1.ID= Table2.ID;
这是解决这个问题最简单,最快捷的方法。