如何将单列值分割为多个列值？
我有一个问题，将单列值分成多个列值。
例如：
Name ------------ abcd efgh ijk lmn opq asd j. asdjja asb (asdfas) asd asd 我需要这样的输出：
first_name last_name ---------------------------------- abcd efgh ijk opq asd asdjja asb asd asd null
中间名称可以省略（不需要中间名称）列已经创build，需要插入单个Name列中的数据。
你的方法不会正确处理大量的名字，但…
SELECT CASE WHEN name LIKE '% %' THEN LEFT(name, Charindex(' ', name) - 1) ELSE name END, CASE WHEN name LIKE '% %' THEN RIGHT(name, Charindex(' ', Reverse(name)) - 1) END FROM YourTable
马丁的替代品
select LEFT(name, CHARINDEX(' ', name + ' ') -1), STUFF(name, 1, Len(Name) +1- CHARINDEX(' ',Reverse(name)), '') from somenames
示例表
create table somenames (Name varchar(100)) insert somenames select 'abcd efgh' insert somenames select 'ijk lmn opq' insert somenames select 'asd j. asdjja' insert somenames select 'asb (asdfas) asd' insert somenames select 'asd' insert somenames select '' insert somenames select null
你需要的是一个分离的用户定义函数。 这样，解决scheme看起来像
With SplitValues As ( Select T.Name, Z.Position, Z.Value , Row_Number() Over ( Partition By T.Name Order By Z.Position ) As Num From Table As T Cross Apply dbo.udf_Split( T.Name, ' ' ) As Z ) Select Name , FirstName.Value , Case When ThirdName Is Null Then SecondName Else ThirdName End As LastName From SplitValues As FirstName Left Join SplitValues As SecondName On S2.Name = S1.Name And S2.Num = 2 Left Join SplitValues As ThirdName On S2.Name = S1.Name And S2.Num = 3 Where FirstName.Num = 1
这是一个示例分割函数：
Create Function [dbo].[udf_Split] ( @DelimitedList nvarchar(max) , @Delimiter nvarchar(2) = ',' ) RETURNS TABLE AS RETURN ( With CorrectedList As ( Select Case When Left(@DelimitedList, Len(@Delimiter)) <> @Delimiter Then @Delimiter Else '' End + @DelimitedList + Case When Right(@DelimitedList, Len(@Delimiter)) <> @Delimiter Then @Delimiter Else '' End As List , Len(@Delimiter) As DelimiterLen ) , Numbers As ( Select TOP( Coalesce(DataLength(@DelimitedList)/2,0) ) Row_Number() Over ( Order By c1.object_id ) As Value From sys.columns As c1 Cross Join sys.columns As c2 ) Select CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen As Position , Substring ( CL.List , CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen , CharIndex(@Delimiter, CL.list, N.Value + 1) - ( CharIndex(@Delimiter, CL.list, N.Value) + CL.DelimiterLen ) ) As Value From CorrectedList As CL Cross Join Numbers As N Where N.Value <= DataLength(CL.List) / 2 And Substring(CL.List, N.Value, CL.DelimiterLen) = @Delimiter )
;WITH Split_Names (Name, xmlname) AS ( SELECT Name, CONVERT(XML,'<Names><name>' + REPLACE(Name,' ', '</name><name>') + '</name></Names>') AS xmlname FROM somenames ) SELECT xmlname.value('/Names[1]/name[1]','varchar(100)') AS first_name, xmlname.value('/Names[1]/name[2]','varchar(100)') AS last_name FROM Split_Names
并检查以下链接以供参考
http://jahaines.blogspot.in/2009/06/converting-delimited-string-of-values.html
下面是我在SQLite数据库上做了这个工作：
SELECT SUBSTR(name, 1,INSTR(name, " ")-1) as Firstname, SUBSTR(name, INSTR(name," ")+1, LENGTH(name)) as Lastname FROM YourTable;
希望它有帮助。
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(rent, ' ', 1), ' ', -1) AS currency, SUBSTRING_INDEX(SUBSTRING_INDEX(rent, ' ', 3), ' ', -1) AS rent FROM tolets
