使用UIView animateWithDurationanimation时，不能触摸UIButton

我有以下代码：

[UIView animateWithDuration:0.3 delay:0.0 options:UIViewAnimationCurveEaseOut | UIViewAnimationOptionAllowUserInteraction animations:^{ CGRect r = [btn frame]; r.origin.y -= 40; [btn setFrame: r]; } completion:^(BOOL done){ if(done){ [UIView animateWithDuration:0.3 delay:1 options:UIViewAnimationOptionCurveEaseIn | UIViewAnimationOptionAllowUserInteraction animations:^{ CGRect r = [btn frame]; r.origin.y += 40; [btn setFrame: r]; } completion:^(BOOL done){if(done) zombiePopping = 0; }]; } }]; 

问题是，似乎button没有响应触摸animation时，即使我使用UIViewAnimationOptionAllowInteraction ，这是UIViewAnimationOptionAllowInteraction我。

也许这最核心的animation工作？ 如果是的话，我将如何去呢？

Answer 1

animation时，button的可触摸部分与button的可见框不一致。

在内部，button的框架将被设置为animation的最终值。 你应该发现，你可以在这个领域挖掘，它会工作。

要打一个移动的button，你需要对button的.layer.presentationLayer属性进行testing（需要导入QuartzCore框架来完成）。 这通常会在视图控制器中的触摸处理方法中完成。

如果您需要更多，我很乐意扩大这个答案。

这里是如何通过命中testing表示层来响应触摸事件。 此代码位于正在pipe理button的视图控制器子类中。 当我这样做时，我对初始触摸感兴趣，而不是触摸结束（这通常是一个水龙头会注册的），但原理是一样的。

记得导入QuartzCore框架并将其添加到您的项目。

 - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [touches anyObject]; CGPoint touchLocation = [touch locationInView:self.view]; for (UIButton *button in self.buttonsOutletCollection) { if ([button.layer.presentationLayer hitTest:touchLocation]) { // This button was hit whilst moving - do something with it here break; } } } 

Answer 2

在我的情况下，我设置superView.alpha = 0，它停止button的交互，虽然我设置UIViewAnimationOptionAllowUserInteraction 。

解？ 简单，只需将alpha减less到0.1而不是0

 [UIView animateWithDuration:durationTime delay:0 options:UIViewAnimationOptionAllowUserInteraction | UIViewAnimationOptionOverrideInheritedOptions | UIViewAnimationOptionCurveEaseInOut | UIViewAnimationOptionRepeat | UIViewAnimationOptionAutoreverse animations: ^{ superView.alpha = 0.1; // 0.0 will make the button unavailable to touch } completion:nil]; 

Answer 3

选项的顺序很重要，您必须首先放置UIViewAnimationOptionAllowUserInteraction ，然后添加其他选项。

在Swift 3中使用： .allowUserInteraction

Answer 4

我已经使用NSTimer实现了这个function：首先，执行启动animation，然后启动一个计时器，这是演示代码：

 -(void)fun··· { [UIView animateWithDuration:0.3 delay:0.0 options:UIViewAnimationCurveEaseOut | UIViewAnimationOptionAllowUserInteraction animations:^{ CGRect r = [btn frame]; r.origin.y -= 40; [btn setFrame: r]; } completion:^(BOOL done){}]; then , you should start an timer,example: //start timer if (timer != nil) { [timer invalidate]; timer = nil; } [self performSelector:@selector(closeButton) withObject:nil afterDelay:0]; } - (void)closeButton { if (timer != nil) { return; } //start timer timer = [NSTimer scheduledTimerWithTimeInterval:1.5f target:self selector:@selector(timerEvent) userInfo:nil repeats:NO]; [[NSRunLoop currentRunLoop] addTimer:timer forMode:NSRunLoopCommonModes]; } - (void)timerEvent { [UIView animateWithDuration:0.3 delay:1 options:UIViewAnimationOptionCurveEaseIn | UIViewAnimationOptionAllowUserInteraction animations:^{ CGRect r = [btn frame]; r.origin.y += 40; [btn setFrame: r]; } completion:^(BOOL done){if(done) zombiePopping = 0; }]; [timer invalidate]; timer = nil; } 

Answer 5

在Swift（2.0）中的相同答案，为懒惰。 如有必要，请用循环和sockets集合replace：

 override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) { let touch = touches.first let touchLocation = touch!.locationInView(self.view) if self.button.layer.presentationLayer()!.hitTest(touchLocation) != nil { action() // Your action, preferably the original button action. } } 

Answer 6

Swift版本： '999'是用于标识目标视图的标签值。

 override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) { let touch = touches.first let touchLocation = (touch?.locationInView(self.rootView))! for view in self.view.subviews { if let layer = view.layer.presentationLayer()?.hitTest(touchLocation) where view.tag == 999 { // Here view is the tapped view print(view) } } } 

Answer 7

奇迹般有效

override func hitTest(point: CGPoint, withEvent event: UIEvent?) -> UIView? { if bounds.contains(point) && !hidden && userInteractionEnabled && enabled { return self } return super.hitTest(point, withEvent: event) }

虽然这个答案也是正确的

Answer 8

Swift 3.0在viewdidload顶部创build一个超级视图

 let superView = UIView(frame: view.frame) superView.isUserInteractionEnabled = true superView.backgroundColor = UIColor.clear superView.alpha = 0.1 view.addSubview(superView) 

现在就这样实行touchesbagan

 override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) { guard let touch = (touches as NSSet).anyObject() as? UITouch else { return } let touchLocation = touch.location(in: self.view) if btnone.layer.presentation()?.hitTest(touchLocation) != nil { print("1") // Do stuff for button } if btntwo.layer.presentation()?.hitTest(touchLocation) != nil { print("2") // Do stuff } if btnthree.layer.presentation()?.hitTest(touchLocation) != nil { print(3) // Do stuff } if btnfour.layer.presentation()?.hitTest(touchLocation) != nil { print(4) // Do stuff } }