在T-SQL中相当于分割函数？
我正在寻找拆分'1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 …'（逗号分隔）到表或表variables。
有没有人有一个函数返回每一个连续？
这里有点过时的解决scheme：
/* Splits string into parts delimitered with specified character. */ CREATE FUNCTION [dbo].[SDF_SplitString] ( @sString nvarchar(2048), @cDelimiter nchar(1) ) RETURNS @tParts TABLE ( part nvarchar(2048) ) AS BEGIN if @sString is null return declare @iStart int, @iPos int if substring( @sString, 1, 1 ) = @cDelimiter begin set @iStart = 2 insert into @tParts values( null ) end else set @iStart = 1 while 1=1 begin set @iPos = charindex( @cDelimiter, @sString, @iStart ) if @iPos = 0 set @iPos = len( @sString )+1 if @iPos - @iStart > 0 insert into @tParts values ( substring( @sString, @iStart, @iPos-@iStart )) else insert into @tParts values( null ) set @iStart = @iPos+1 if @iStart > len( @sString ) break end RETURN END 在SQL Server 2008中，您可以使用.NET代码实现相同的function。 也许这会工作得更快，但肯定这种方法更容易pipe理。
尝试这个
DECLARE @xml xml, @str varchar(100), @delimiter varchar(10) SET @str = '1,2,3,4,5,6,7,8,9,10,11,12,13,14,15' SET @delimiter = ',' SET @xml = cast(('<X>'+replace(@str, @delimiter, '</X><X>')+'</X>') as xml) SELECT C.value('.', 'varchar(10)') as value FROM @xml.nodes('X') as X(C)
要么
DECLARE @str varchar(100), @delimiter varchar(10) SET @str = '1,2,3,4,5,6,7,8,9,10,11,12,13,14,15' SET @delimiter = ',' ;WITH cte AS ( SELECT 0 a, 1 b UNION ALL SELECT b, CHARINDEX(@delimiter, @str, b) + LEN(@delimiter) FROM CTE WHERE b > a ) SELECT SUBSTRING(@str, a, CASE WHEN b > LEN(@delimiter) THEN b - a - LEN(@delimiter) ELSE LEN(@str) - a + 1 END) value FROM cte WHERE a > 0
更多的方法做同样的事情在这里如何分割逗号分隔的string？
你已经标记了这个SQL Server 2008，但是这个问题的未来访问者（使用SQL Server 2016+）可能想知道关于STRING_SPLIT 。
有了这个新的内置函数，你现在可以使用
SELECT TRY_CAST(value AS INT) FROM STRING_SPLIT ('1,2,3,4,5,6,7,8,9,10,11,12,13,14,15', ',')
这个function的一些限制和一些有希望的性能testing结果在这篇博文中由Aaron Bertrand提供 。
对于那些熟悉这个function的人来说，这就像.NET一样。
CREATE FUNCTION dbo.[String.Split] ( @Text VARCHAR(MAX), @Delimiter VARCHAR(100), @Index INT ) RETURNS VARCHAR(MAX) AS BEGIN DECLARE @A TABLE (ID INT IDENTITY, V VARCHAR(MAX)); DECLARE @R VARCHAR(MAX); WITH CTE AS ( SELECT 0 A, 1 B UNION ALL SELECT B, CONVERT(INT,CHARINDEX(@Delimiter, @Text, B) + LEN(@Delimiter)) FROM CTE WHERE B > A ) INSERT @A(V) SELECT SUBSTRING(@Text,A,CASE WHEN B > LEN(@Delimiter) THEN BA-LEN(@Delimiter) ELSE LEN(@Text) - A + 1 END) VALUE FROM CTE WHERE A >0 SELECT @R = V FROM @A WHERE ID = @Index + 1 RETURN @R END SELECT dbo.[String.Split]('121,2,3,0',',',1) -- gives '2'
这是你问的分裂function
CREATE FUNCTION [dbo].[split]( @delimited NVARCHAR(MAX), @delimiter NVARCHAR(100) ) RETURNS @t TABLE (id INT IDENTITY(1,1), val NVARCHAR(MAX)) AS BEGIN DECLARE @xml XML SET @xml = N'<t>' + REPLACE(@delimited,@delimiter,'</t><t>') + '</t>' INSERT INTO @t(val) SELECT r.value('.','varchar(MAX)') as item FROM @xml.nodes('/t') as records(r) RETURN END
执行这样的function
select * from dbo.split('1,2,3,4,5,6,7,8,9,10,11,12,13,14,15',',')
DECLARE @InputString NVARCHAR(MAX) = 'token1,token2,token3,token4,token5' , @delimiter varchar(10) = ',' DECLARE @xml AS XML = CAST(('<X>'+REPLACE(@InputString,@delimiter ,'</X><X>')+'</X>') AS XML) SELECT C.value('.', 'varchar(10)') AS value FROM @xml.nodes('X') as X(C)
这个回应的来源： http : //sqlhint.com/sqlserver/how-to/best-split-function-tsql-delimited
我很想挤我最喜欢的解决scheme。 结果表将由2列组成：PosIdx表示find的整数的位置; 和整数值。
create function FnSplitToTableInt ( @param nvarchar(4000) ) returns table as return with Numbers(Number) as ( select 1 union all select Number + 1 from Numbers where Number < 4000 ), Found as ( select Number as PosIdx, convert(int, ltrim(rtrim(convert(nvarchar(4000), substring(@param, Number, charindex(N',' collate Latin1_General_BIN, @param + N',', Number) - Number))))) as Value from Numbers where Number <= len(@param) and substring(N',' + @param, Number, 1) = N',' collate Latin1_General_BIN ) select PosIdx, case when isnumeric(Value) = 1 then convert(int, Value) else convert(int, null) end as Value from Found
它使用recursionCTE作为位置列表，默认从1到100。 如果您需要使用超过100的string，只需使用'option（maxrecursion 4000）'调用此函数，如下所示：
select * from FnSplitToTableInt ( '9, 8, 7, 6, 5, 4, 3, 2, 1, 0, ' + '9, 8, 7, 6, 5, 4, 3, 2, 1, 0, ' + '9, 8, 7, 6, 5, 4, 3, 2, 1, 0, ' + '9, 8, 7, 6, 5, 4, 3, 2, 1, 0, ' + '9, 8, 7, 6, 5, 4, 3, 2, 1, 0' ) option (maxrecursion 4000)
这是另一个没有任何限制的版本（例如：使用xml方法时的特殊字符，CTE方法中的logging数），并且基于对源string平均长度为4000的10M +logging的testing运行更快。希望这可以帮助。
Create function [dbo].[udf_split] ( @ListString nvarchar(max), @Delimiter nvarchar(1000), @IncludeEmpty bit) Returns @ListTable TABLE (ID int, ListValue nvarchar(1000)) AS BEGIN Declare @CurrentPosition int, @NextPosition int, @Item nvarchar(max), @ID int, @L int Select @ID = 1, @L = len(replace(@Delimiter,' ','^')), @ListString = @ListString + @Delimiter, @CurrentPosition = 1 Select @NextPosition = Charindex(@Delimiter, @ListString, @CurrentPosition) While @NextPosition > 0 Begin Set @Item = LTRIM(RTRIM(SUBSTRING(@ListString, @CurrentPosition, @NextPosition-@CurrentPosition))) If @IncludeEmpty=1 or LEN(@Item)>0 Begin Insert Into @ListTable (ID, ListValue) Values (@ID, @Item) Set @ID = @ID+1 End Set @CurrentPosition = @NextPosition+@L Set @NextPosition = Charindex(@Delimiter, @ListString, @CurrentPosition) End RETURN END
CREATE FUNCTION Split ( @delimited nvarchar(max), @delimiter nvarchar(100) ) RETURNS @t TABLE ( -- Id column can be commented out, not required for sql splitting string id int identity(1,1), -- I use this column for numbering splitted parts val nvarchar(max) ) AS BEGIN declare @xml xml set @xml = N'<root><r>' + replace(@delimited,@delimiter,'</r><r>') + '</r></root>' insert into @t(val) select r.value('.','varchar(max)') as item from @xml.nodes('//root/r') as records(r) RETURN END GO
用法
Select * from dbo.Split(N'1,2,3,4,6',',')
/* *Object: UserDefinedFunction [dbo].[Split] Script Date: 10/04/2013 18:18:38* */ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO ALTER FUNCTION [dbo].[Split] (@List varchar(8000),@SplitOn Nvarchar(5)) RETURNS @RtnValue table (Id int identity(1,1),Value nvarchar(100)) AS BEGIN Set @List = Replace(@List,'''','') While (Charindex(@SplitOn,@List)>0) Begin Insert Into @RtnValue (value) Select Value = ltrim(rtrim(Substring(@List,1,Charindex(@SplitOn,@List)-1))) Set @List = Substring(@List,Charindex(@SplitOn,@List)+len(@SplitOn),len(@List)) End Insert Into @RtnValue (Value) Select Value = ltrim(rtrim(@List)) Return END go Select * From [Clv].[Split] ('1,2,3,3,3,3,',',') GO
这个博客附带了一个在T-SQL中使用XML的非常好的解决scheme。
这是我基于该博客（根据需要更改函数名称和结果types转换）的function：
SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE FUNCTION [dbo].[SplitIntoBigints] (@List varchar(MAX), @Splitter char) RETURNS TABLE AS RETURN ( WITH SplittedXML AS( SELECT CAST('<v>' + REPLACE(@List, @Splitter, '</v><v>') + '</v>' AS XML) AS Splitted ) SELECT xvvalue('.', 'bigint') AS Value FROM SplittedXML CROSS APPLY Splitted.nodes('//v') x(v) ) GO
CREATE Function [dbo].[CsvToInt] ( @Array varchar(4000)) returns @IntTable table (IntValue int) AS begin declare @separator char(1) set @separator = ',' declare @separator_position int declare @array_value varchar(4000) set @array = @array + ',' while patindex('%,%' , @array) <> 0 begin select @separator_position = patindex('%,%' , @array) select @array_value = left(@array, @separator_position - 1) Insert @IntTable Values (Cast(@array_value as int)) select @array = stuff(@array, 1, @separator_position, '') end
这里使用计数表格是Jeff Moden提供的一个分割string函数（最好的方法）
CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1)) RETURNS TABLE WITH SCHEMABINDING AS RETURN --===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000... -- enough to cover NVARCHAR(4000) WITH E1(N) AS ( SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 ), --10E+1 or 10 rows E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front -- for both a performance gain and prevention of accidental "overruns" SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4 ), cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter) SELECT 1 UNION ALL SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,tN,1) = @pDelimiter ), cteLen(N1,L1) AS(--==== Return start and length (for use in substring) SELECT s.N1, ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000) FROM cteStart s ) --===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found. SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1), Item = SUBSTRING(@pString, l.N1, l.L1) FROM cteLen l ;
来自Tally OH的推荐！ 改进的SQL 8K“CSV分割器”function
你在sql server中写这个函数之后问题就解决了。
http://csharpdotnetsol.blogspot.in/2013/12/csv-function-in-sql-server-for-divide.html
