在swift中使用属性string粗体文本
我有这样的一个string
var str = "@text1 this is good @text1" 现在用另一个stringreplacetext1 ，比如t 1 。 我能够代替文本，但我不能大胆。 我想大胆的新stringt 1 ，以便最终的输出将是：
@t 1这是好的@t 1
我该怎么做？
我看到的所有例子都在Objective-C中，但我想在Swift中完成。
提前致谢。
这是一个很好的方法来在一个标签中使用粗体和普通文本的组合。
延期：
Swift 2.1
extension NSMutableAttributedString { func bold(text:String) -> NSMutableAttributedString { let attrs:[String:AnyObject] = [NSFontAttributeName : UIFont(name: "AvenirNext-Medium", size: 12)!] let boldString = NSMutableAttributedString(string:"\(text)", attributes:attrs) self.appendAttributedString(boldString) return self } func normal(text:String)->NSMutableAttributedString { let normal = NSAttributedString(string: text) self.appendAttributedString(normal) return self } }
Swift 3.0
extension NSMutableAttributedString { @discardableResult func bold(_ text:String) -> NSMutableAttributedString { let attrs:[String:AnyObject] = [NSFontAttributeName: UIFont(name: "AvenirNext-Medium", size: 12)!] let boldString = NSMutableAttributedString(string: text, attributes:attrs) self.append(boldString) return self } @discardableResult func normal(_ text:String)->NSMutableAttributedString { let normal = NSAttributedString(string: text) self.append(normal) return self } }
斯威夫特4
extension NSMutableAttributedString { @discardableResult func bold(_ text: String) -> NSMutableAttributedString { let attrs: [NSAttributedStringKey: Any] = [.font: UIFont(name: "AvenirNext-Medium", size: 12)!] let boldString = NSMutableAttributedString(string:text, attributes: attrs) append(boldString) return self } @discardableResult func normal(_ text: String) -> NSMutableAttributedString { let normal = NSAttributedString(string: text) append(normal) return self } }
用法：
let formattedString = NSMutableAttributedString() formattedString .bold("Bold Text") .normal(" Normal Text ") .bold("Bold Text") let lbl = UILabel() lbl.attributedText = formattedString
结果：
粗体文本正常文本粗体文本
var normalText = "Hi am normal" var boldText = "And I am BOLD!" var attributedString = NSMutableAttributedString(string:normalText) var attrs = [NSFontAttributeName : UIFont.boldSystemFont(ofSize: 15)] var boldString = NSMutableAttributedString(string:boldText, attributes:attrs) attributedString.appendAttributedString(boldString)
当你想把它分配给一个标签时：
yourLabel.attributedText = attributedString
编辑/更新： Xcode 8.3.2•Swift 3.1
如果您了解HTML和CSS，则可以使用它轻松控制字符样式，颜色和属性string的大小，如下所示：
extension String { var html2AttStr: NSAttributedString? { return try? NSAttributedString(data: Data(utf8), options: [NSDocumentTypeDocumentAttribute: NSHTMLTextDocumentType, NSCharacterEncodingDocumentAttribute: String.Encoding.utf8.rawValue], documentAttributes: nil) } } "<style type=\"text/css\">#red{color:#F00}#green{color:#0F0}#blue{color: #00F; font-weight: Bold; font-size: 32}</style><span id=\"red\" >Red,</span><span id=\"green\" > Green </span><span id=\"blue\">and Blue</span>".html2AttStr
这是我提出的最好的方式。 添加一个可以从任何地方调用的函数，并将其添加到文件中，而不需要像Constants.swift这样的类，然后通过调用一行代码就可以在任何string中强化单词：
要进入constants.swift文件：
import Foundation import UIKit func addBoldText(fullString: NSString, boldPartOfString: NSString, font: UIFont!, boldFont: UIFont!) -> NSAttributedString { let nonBoldFontAttribute = [NSFontAttributeName:font!] let boldFontAttribute = [NSFontAttributeName:boldFont!] let boldString = NSMutableAttributedString(string: fullString as String, attributes:nonBoldFontAttribute) boldString.addAttributes(boldFontAttribute, range: fullString.rangeOfString(boldPartOfString as String)) return boldString }
然后，你可以为任何UILabel调用这一行代码：
self.UILabel.attributedText = addBoldText("Check again in 30 DAYS to find more friends", boldPartOfString: "30 DAYS", font: normalFont!, boldFont: boldSearchFont!) //Mark: Albeit that you've had to define these somewhere: let normalFont = UIFont(name: "INSERT FONT NAME", size: 15) let boldFont = UIFont(name: "INSERT BOLD FONT", size: 15)
如果您正在使用本地化的string，则可能无法依靠始终处于句末的粗体string。 如果是这种情况，那么下面的工作很好：
例如查询“blah”不匹配任何项目
/* Create the search query part of the text, eg "blah". The variable 'text' is just the value entered by the user. */ let searchQuery = "\"\(text)\"" /* Put the search text into the message */ let message = "Query \(searchQuery). does not match any items" /* Find the position of the search string. Cast to NSString as we want range to be of type NSRange, not Swift's Range<Index> */ let range = (message as NSString).rangeOfString(searchQuery) /* Make the text at the given range bold. Rather than hard-coding a text size, Use the text size configured in Interface Builder. */ let attributedString = NSMutableAttributedString(string: message) attributedString.addAttribute(NSFontAttributeName, value: UIFont.boldSystemFontOfSize(label.font.pointSize), range: range) /* Put the text in a label */ label.attributedText = attributedString
我扩展了David West的伟大的答案，以便您可以input一个string，并告诉它你想要的所有子string：
func addBoldText(fullString: NSString, boldPartsOfString: Array<NSString>, font: UIFont!, boldFont: UIFont!) -> NSAttributedString { let nonBoldFontAttribute = [NSFontAttributeName:font!] let boldFontAttribute = [NSFontAttributeName:boldFont!] let boldString = NSMutableAttributedString(string: fullString as String, attributes:nonBoldFontAttribute) for i in 0 ..< boldPartsOfString.count { boldString.addAttributes(boldFontAttribute, range: fullString.rangeOfString(boldPartsOfString[i] as String)) } return boldString }
然后像这样调用它：
let normalFont = UIFont(name: "Dosis-Medium", size: 18) let boldSearchFont = UIFont(name: "Dosis-Bold", size: 18) self.UILabel.attributedText = addBoldText("Check again in 30 days to find more friends", boldPartsOfString: ["Check", "30 days", "find", "friends"], font: normalFont!, boldFont: boldSearchFont!)
这将会增强你想要在给定string中加粗的所有子string
这可能是有用的
class func createAttributedStringFrom (string1 : String ,strin2 : String, attributes1 : Dictionary<String, NSObject>, attributes2 : Dictionary<String, NSObject>) -> NSAttributedString{ let fullStringNormal = (string1 + strin2) as NSString let attributedFullString = NSMutableAttributedString(string: fullStringNormal as String) attributedFullString.addAttributes(attributes1, range: fullStringNormal.rangeOfString(string1)) attributedFullString.addAttributes(attributes2, range: fullStringNormal.rangeOfString(strin2)) return attributedFullString }
基于杰里米·贝德（Jeremy Bader）和戴维·韦斯特（David West）的杰出答案，斯威夫特3延伸：
extension String { func withBoldText(boldPartsOfString: Array<NSString>, font: UIFont!, boldFont: UIFont!) -> NSAttributedString { let nonBoldFontAttribute = [NSFontAttributeName:font!] let boldFontAttribute = [NSFontAttributeName:boldFont!] let boldString = NSMutableAttributedString(string: self as String, attributes:nonBoldFontAttribute) for i in 0 ..< boldPartsOfString.count { boldString.addAttributes(boldFontAttribute, range: (self as NSString).range(of: boldPartsOfString[i] as String)) } return boldString } }
用法：
let label = UILabel() let font = UIFont(name: "AvenirNext-Italic", size: 24)! let boldFont = UIFont(name: "AvenirNext-BoldItalic", size: 24)! label.attributedText = "Make sure your face is\nbrightly and evenly lit".withBoldText( boldPartsOfString: ["brightly", "evenly"], font: font, boldFont: boldFont)
Swift 3.0
将html转换为string和字体根据您的要求更改。
do { let str = try NSAttributedString(data: ("I'm a normal text and <b>this is my bold part . </b>And I'm again in the normal text".data(using: String.Encoding.unicode, allowLossyConversion: true)!), options: [ NSDocumentTypeDocumentAttribute: NSHTMLTextDocumentType], documentAttributes: nil) myLabel.attributedText = str myLabel.font = MONTSERRAT_BOLD(23) myLabel.textAlignment = NSTextAlignment.left } catch { print(error) }
func MONTSERRAT_BOLD(_ size: CGFloat) -> UIFont { return UIFont(name: "MONTSERRAT-BOLD", size: size)! }
改善Prajeet Shrestha答案：
你可以为NSMutableAttributedString做一个通用的扩展，它涉及的代码较less。 在这种情况下，我select了使用系统字体，但是您可以使用它来input字体名称作为参数。
extension NSMutableAttributedString { func systemFontWith(text: String, size: CGFloat, weight: CGFloat) -> NSMutableAttributedString { let attributes: [String: AnyObject] = [NSFontAttributeName: UIFont.systemFont(ofSize: size, weight: weight)] let string = NSMutableAttributedString(string: text, attributes: attributes) self.append(string) return self } }
