将string转换为JSON数组

我有一个来自Web服务的JSONstring，并试图将其转换为JSON数组

{ "locations": [ { "lat": "23.053", "long": "72.629", "location": "ABC", "address": "DEF", "city": "Ahmedabad", "state": "Gujrat", "phonenumber": "1234567" }, { "lat": "23.053", "long": "72.629", "location": "ABC", "address": "DEF", "city": "Ahmedabad", "state": "Gujrat", "phonenumber": "1234567" }, { "lat": "23.053", "long": "72.629", "location": "ABC", "address": "DEF", "city": "Ahmedabad", "state": "Gujrat", "phonenumber": "1234567" }, { "lat": "23.053", "long": "72.629", "location": "ABC", "address": "DEF", "city": "Ahmedabad", "state": "Gujrat", "phonenumber": "1234567" }, { "lat": "23.053", "long": "72.629", "location": "ABC", "address": "DEF", "city": "Ahmedabad", "state": "Gujrat", "phonenumber": "1234567" } ] } 

我在线validation了这个string，这似乎是正确的。 现在我在android开发中使用下面的代码来利用

 JSONArray jsonArray = new JSONArray(readlocationFeed); 

这引发了typemismatch的exception。

我不明白这个问题，因为我是新手到Android以及Java。

Answer 1

在这里你得到JSONObject所以改变

 JSONArray jsonArray = new JSONArray(readlocationFeed); 

跟随以下

 JSONObject jsnobject = new JSONObject(readlocationFeed); 

之后

 JSONArray jsonArray = jsnobject.getJSONArray("locations"); for (int i = 0; i < jsonArray.length(); i++) { JSONObject explrObject = jsonArray.getJSONObject(i); } 

Answer 2

您将需要将给定的string转换为JSONObject而不是JSONArray因为当前String包含JsonObject而不是JsonArray根元素：

 JSONObject jsonObject = new JSONObject(readlocationFeed); 

Answer 3

inputstring

 [ { "userName": "sandeep", "age": 30 }, { "userName": "vivan", "age": 5 } ] 

简单的方法将string转换为JSON

 public class Test { public static void main(String[] args) throws JSONException { String data = "[{\"userName\": \"sandeep\",\"age\":30},{\"userName\": \"vivan\",\"age\":5}] "; JSONArray jsonArr = new JSONArray(data); for (int i = 0; i < jsonArr.length(); i++) { JSONObject jsonObj = jsonArr.getJSONObject(i); System.out.println(jsonObj); } } } 

产量

 {"userName":"sandeep","age":30} {"userName":"vivan","age":5} 

Answer 4

使用json lib： –

 String data="[{"A":"a","B":"b","C":"c","D":"d","E":"e","F":"f","G":"g"}]"; Object object=null; JSONArray arrayObj=null; JSONParser jsonParser=new JSONParser(); object=jsonParser.parse(data); arrayObj=(JSONArray) object; System.out.println("Json object :: "+arrayObj); 

使用GSON库： –

 Gson gson = new Gson(); String data="[{\"A\":\"a\",\"B\":\"b\",\"C\":\"c\",\"D\":\"d\",\"E\":\"e\",\"F\":\"f\",\"G\":\"g\"}]"; JsonParser jsonParser = new JsonParser(); JsonArray jsonArray = (JsonArray) jsonParser.parse(data); 

Answer 5

 try { Log.e("log_tag", "Error in convert String" + result.toString()); JSONObject json_data = new JSONObject(result); String status = json_data.getString("Status"); { String data = json_data.getString("locations"); JSONArray json_data1 = new JSONArray(data); for (int i = 0; i < json_data1.length(); i++) { json_data = json_data1.getJSONObject(i); String lat= json_data.getString("lat"); String lng= json_data.getString("long"); } } 

Answer 6

 String b = "[" + readlocationFeed + "]"; JSONArray jsonArray1 = new JSONArray(b); jsonarray_length1 = jsonArray1.length(); for (int i = 0; i < jsonarray_length1; i++) { } 

或者在JSONOBJECT中进行转换

 JSONObject jsonobj = new JSONObject(readlocationFeed); JSONArray jsonArray = jsonobj.getJSONArray("locations"); 

Answer 7

如果回应是这样的

 "GetDataResult": "[{\"UserID\":1,\"DeviceID\":\"d1254\",\"MobileNO\":\"056688\",\"Pak1\":true,\"pak2\":true,\"pak3\":false,\"pak4\":true,\"pak5\":true,\"pak6\":false,\"pak7\":false,\"pak8\":true,\"pak9\":false,\"pak10\":true,\"pak11\":false,\"pak12\":false}]" 

你可以像这样parsing

 JSONObject jobj=new JSONObject(response); String c = jobj.getString("GetDataResult"); JSONArray jArray = new JSONArray(c); deviceId=jArray.getJSONObject(0).getString("DeviceID"); 

这里JsonArray的大小是1.否则你应该使用for循环获取值。

Answer 8

您可以执行以下操作：

 JSONArray jsonArray = jsnobject.getJSONArray("locations"); for (int i = 0; i < jsonArray.length(); i++) { JSONObject explrObject = jsonArray.getJSONObject(i); } 

Answer 9

如果从Web服务跟随JSON，Json数组作为响应：

  [3] 0: { id: 2 name: "a561137" password: "test" firstName: "abhishek" lastName: "ringsia" organization: "bbb" }- 1: { id: 3 name: "a561023" password: "hello" firstName: "hello" lastName: "hello" organization: "hello" }- 2: { id: 4 name: "a541234" password: "hello" firstName: "hello" lastName: "hello" organization: "hello" } 

必须先接受它作为Json数组，然后在读取它的Object时必须使用Object Mapper.readValue，因为Json Object Still in String。

  List<User> list = new ArrayList<User>(); JSONArray jsonArr = new JSONArray(response); for (int i = 0; i < jsonArr.length(); i++) { JSONObject jsonObj = jsonArr.getJSONObject(i); ObjectMapper mapper = new ObjectMapper(); User usr = mapper.readValue(jsonObj.toString(), User.class); list.add(usr); } 

mapper.read是正确的function，如果你使用mapper.convert（param，param）。 它会给你错误。

Answer 10

 //A very simple way to convert import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import com.google.gson.Gson; import com.google.gson.JsonArray; import com.google.gson.JsonElement; import com.google.gson.JsonParser; class Usuario { private String username; private String email; private Integer credits; private String twitter_username; public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public Integer getCredits() { return credits; } public void setCredits(Integer credits) { this.credits = credits; } public String getTwitter_username() { return twitter_username; } public void setTwitter_username(String twitter_username) { this.twitter_username = twitter_username; } @Override public String toString() { return "UserName: " + this.getUsername() + " Email: " + this.getEmail(); } 

}

 /* * put string into file jsonFileArr.json * [{"username":"Hello","email":"[e-mail]","credits" * :"100","twitter_username":""}, * {"username":"Goodbye","email":"[e-mail]" * ,"credits":"0","twitter_username":""}, * {"username":"mlsilva","email":"[e-mail]" * ,"credits":"524","twitter_username":""}, * {"username":"fsouza","email":"[e-mail]" * ,"credits":"1052","twitter_username":""}] */ public class TestaGsonLista { public static void main(String[] args) { Gson gson = new Gson(); try { BufferedReader br = new BufferedReader(new FileReader( "C:\\Temp\\jsonFileArr.json")); JsonArray jsonArray = new JsonParser().parse(br).getAsJsonArray(); for (int i = 0; i < jsonArray.size(); i++) { JsonElement str = jsonArray.get(i); Usuario obj = gson.fromJson(str, Usuario.class); System.out.println(obj); System.out.println(str); System.out.println("-------"); } } catch (IOException e) { e.printStackTrace(); } } 

}