什么是最简单的SQL查询find第二大的价值？

什么是最简单的SQL查询来查找特定列中的第二大整数值？

列中可能有重复的值。

Answer 1

SELECT MAX( col ) FROM table WHERE col < ( SELECT MAX( col ) FROM table ) 

Answer 2

 SELECT MAX(col) FROM table WHERE col NOT IN (SELECT MAX(col) FROM table); 

Answer 3

在T-SQL中有两种方法：

 --filter out the max select max( col ) from [table] where col < ( select max( col ) from [table] ) --sort top two then bottom one select top 1 col from ( select top 2 col from [table] order by col) topTwo order by col desc 

在Microsoft SQL中，第一种方法比第二种方法快两倍，即使所讨论的列是聚集的。

这是因为与max聚合使用的表或索引扫描相比，sorting操作相对较慢。

或者，在Microsoft SQL 2005及更高版本中，您可以使用ROW_NUMBER()函数：

 select col from ( select ROW_NUMBER() over (order by col asc) as 'rowNum', col from [table] ) withRowNum where rowNum = 2 

Answer 4

我在这里看到了一些SQL Server特定的和一些MySQL特定的解决scheme，所以你可能想弄清楚你需要哪个数据库。 虽然如果我不得不猜测我会说SQL Server，因为这在MySQL中是微不足道的。

我也看到一些解决scheme不能工作，因为他们没有考虑到重复的可能性，所以要小心哪些是你接受的。 最后，我看到了一些可以工作但是会对表格进行两次完整扫描的工具。 你想确保第二次扫描只看2个值。

SQL Server（2012之前）：

 SELECT MIN([column]) AS [column] FROM ( SELECT TOP 2 [column] FROM [Table] GROUP BY [column] ORDER BY [column] DESC ) a 

MySQL的：

 SELECT `column` FROM `table` GROUP BY `column` ORDER BY `column` DESC LIMIT 1,1 

更新：

SQL Server 2012现在支持更清晰（和标准 ）的OFFSET / FETCH语法：

 SELECT TOP 2 [column] FROM [Table] GROUP BY [column] ORDER BY [column] DESC OFFSET 1 ROWS FETCH NEXT 1 ROWS ONLY; 

Answer 5

我想你可以做这样的事情：

 SELECT * FROM Table ORDER BY NumericalColumn DESC LIMIT 1 OFFSET 1 

要么

 SELECT * FROM Table ORDER BY NumericalColumn DESC LIMIT (1, 1) 

取决于你的数据库服务器。 提示：SQL Server不会执行LIMIT。

Answer 6

最简单的方法是从应用程序中的结果集中获取第二个值：

 SELECT DISTINCT value FROM Table ORDER BY value DESC LIMIT 2 

但是，如果您必须使用SQLselect第二个值，那么：

 SELECT MIN(value) FROM (SELECT DISTINCT value FROM Table ORDER BY value DESC LIMIT 2) AS t 

Answer 7

您可以使用以下查询find列的第二大值

 SELECT * FROM TableName a WHERE 2 = (SELECT count(DISTINCT(b.ColumnName)) FROM TableName b WHERE a.ColumnName <= b.ColumnName); 

你可以在下面的链接find更多的细节

http://www.abhishekbpatel.com/2012/12/how-to-get-nth-maximum-and-minimun.html

Answer 8

一个非常简单的查询来查找第二大的值

 SELECT `Column` FROM `Table` ORDER BY `Column` DESC LIMIT 1,1; 

Answer 9

 SELECT MAX(Salary) FROM Employee WHERE Salary NOT IN (SELECT MAX(Salary) FROM Employee ) 

该查询将返回结果中的最高工资 – 不包含总表中的最高工资。

Answer 10

 select * from (select ROW_NUMBER() over (Order by Col_x desc) as Row, Col_1 from table_1)as table_new tn inner join table_1 t1 on tn.col_1 = t1.col_1 where row = 2 

希望这有助于获得任何行的价值…..

Answer 11

最简单的

 select sal from salary order by sal desc limit 1 offset 1 

Answer 12

老问题我知道，但这给了我一个更好的执行计划：

  SELECT TOP 1 LEAD(MAX (column)) OVER (ORDER BY column desc) FROM TABLE GROUP BY column 

Answer 13

 select min(sal) from emp where sal in (select TOP 2 (sal) from emp order by sal desc) 

注意

sal是col的名字
emp是表名

Answer 14

Tom，相信在select max([COLUMN_NAME]) from [TABLE_NAME]部分的select max([COLUMN_NAME]) from [TABLE_NAME]返回多个值时会失败。 即数据集中有多于2个值的地方。

稍微修改您的查询将工作 –

 select max([COLUMN_NAME]) from [TABLE_NAME] where [COLUMN_NAME] **IN** ( select max([COLUMN_NAME]) from [TABLE_NAME] ) 

Answer 15

 select max(COL_NAME) from TABLE_NAME where COL_NAME in (select COL_NAME from TABLE_NAME where COL_NAME < (select max(COL_NAME) from TABLE_NAME)); 

子查询返回除最大值以外的所有值。 从返回的列表中select最大值。

Answer 16

 select col_name from ( select dense_rank() over (order by col_name desc) as 'rank', col_name from table_name ) withrank where rank = 2 

Answer 17

 SELECT * FROM table WHERE column < (SELECT max(columnq) FROM table) ORDER BY column DESC LIMIT 1 

Answer 18

这是最狡猾的方式：

 SELECT Column name FROM Table name ORDER BY Column name DESC LIMIT 1,1 

Answer 19

正如你提到的重复值。 在这种情况下，您可以使用DISTINCT和GROUP BY来查找第二高的值

这是一张桌子

薪水

：

通过…分组

 SELECT amount FROM salary GROUP by amount ORDER BY amount DESC LIMIT 1 , 1 

不同

 SELECT DISTINCT amount FROM salary ORDER BY amount DESC LIMIT 1 , 1 

LIMIT =起始索引的第一部分

LIMIT的第二部分=多less个值

Answer 20

像这样的东西？ 虽然我没有testing过，

 select top 1 x from ( select top 2 distinct x from y order by x desc ) z order by x 

Answer 21

请参阅如何selectSQL数据库表中的第n行？ 。

Sybase SQL Anywhere支持：

 SELECT TOP 1 START AT 2 value from table ORDER BY value 

Answer 22

使用相关查询：

 Select * from x x1 where 1 = (select count(*) from x where x1.a < a) 

Answer 23

 select * from emp e where 3>=(select count(distinct salary) from emp where s.salary<=salary) 

该查询select最多三个工资。 如果两个emp获得相同的薪水，这不会影响查询。

Answer 24

 select top 1 MyIntColumn from MyTable where MyIntColumn <> (select top 1 MyIntColumn from MyTable order by MyIntColumn desc) order by MyIntColumn desc 

Answer 25

这在MS SQL中工作：

 select max([COLUMN_NAME]) from [TABLE_NAME] where [COLUMN_NAME] < ( select max([COLUMN_NAME]) from [TABLE_NAME] ) 

Answer 26

查询查找行中第二个最高的数字 –

 select Top 1 (salary) from XYZ where Salary not in (select distinct TOP 1(salary) from XYZ order by Salary desc) ORDER BY Salary DESC 

通过改变突出显示的Top 1到TOP 2或4你可以find第三，第四和第五最高分别。

Answer 27

我们也可以使用order by和top 1元素，如下所示：

 Select top 1 col_name from table_name where col_name < (Select top 1 col_name from table_name order by col_name desc) order by col_name desc 

Answer 28

 SELECT * FROM EMP WHERE salary= (SELECT MAX(salary) FROM EMP WHERE salary != (SELECT MAX(salary) FROM EMP) ); 

Answer 29

这是查找列的第二大值的另一种方式。考虑表格'学生'和列'年龄'。然后查询是，

 select top 1 Age from Student where Age in(select distinct top 2 Age from Student order by Age desc) order by Age asc 

Answer 30

尝试：

 select a.* ,b.* from (select * from (select ROW_NUMBER() OVER(ORDER BY fc_amount desc) SrNo1, fc_amount as amount1 From entry group by fc_amount) tbl where tbl.SrNo1 = 2) a , (select * from (select ROW_NUMBER() OVER(ORDER BY fc_amount asc) SrNo2, fc_amount as amount2 From entry group by fc_amount) tbl where tbl.SrNo2 =2) b