如何列出在SQL Server中引用给定表的所有外键？

我需要删除SQL Server数据库中高度被引用的表。 我怎样才能得到所有的外键约束，我将需要删除，以删除表的列表？

（在管理工作室的图形用户界面中点击SQL应该更好。）

Answer 1

不知道为什么没有人建议，但我使用sp_fkeys查询给定的表的外键：

 EXEC sp_fkeys 'TableName' 

Answer 2

我会使用SQL Server管理工作室中的数据库图表功能，但是因为你排除了这一点 – 这在SQL Server 2008中工作（没有2005）。

获取引用表和列名称的列表…

 select t.name as TableWithForeignKey, fk.constraint_column_id as FK_PartNo, c. name as ForeignKeyColumn from sys.foreign_key_columns as fk inner join sys.tables as t on fk.parent_object_id = t.object_id inner join sys.columns as c on fk.parent_object_id = c.object_id and fk.parent_column_id = c.column_id where fk.referenced_object_id = (select object_id from sys.tables where name = 'TableOthersForeignKeyInto') order by TableWithForeignKey, FK_PartNo 

获取外键约束的名称

 select distinct name from sys.objects where object_id in ( select fk.constraint_object_id from sys.foreign_key_columns as fk where fk.referenced_object_id = (select object_id from sys.tables where name = 'TableOthersForeignKeyInto') ) 

Answer 3

尝试这个 ：

 sp_help 'TableName' 

Answer 4

这给你：

• FK本身
• FK所属的模式
• “ 引用表 ”或具有FK的表
• “ 引用列 ”或引用表中指向FK的列
• “ 引用的表 ”或您的FK指向的键列的表
• “ 引用列 ”或FK指向的密钥列

代码如下：

 SELECT obj.name AS FK_NAME, sch.name AS [schema_name], tab1.name AS [table], col1.name AS [column], tab2.name AS [referenced_table], col2.name AS [referenced_column] FROM sys.foreign_key_columns fkc INNER JOIN sys.objects obj ON obj.object_id = fkc.constraint_object_id INNER JOIN sys.tables tab1 ON tab1.object_id = fkc.parent_object_id INNER JOIN sys.schemas sch ON tab1.schema_id = sch.schema_id INNER JOIN sys.columns col1 ON col1.column_id = parent_column_id AND col1.object_id = tab1.object_id INNER JOIN sys.tables tab2 ON tab2.object_id = fkc.referenced_object_id INNER JOIN sys.columns col2 ON col2.column_id = referenced_column_id AND col2.object_id = tab2.object_id 

Answer 5

你也应该介意对其他对象的引用。

如果表被其他表高度引用，则可能也被其他对象（如视图，存储过程，函数等）高度引用。

我真的推荐像SSMS中的“视图依赖”对话框这样的GUI工具，或者像ApexSQL Search这样的免费工具，因为在其他对象中搜索依赖关系可能容易出错，如果只想用SQL来完成。

如果SQL是唯一的选择，你可以尝试这样做。

 select O.name as [Object_Name], C.text as [Object_Definition] from sys.syscomments C inner join sys.all_objects O ON C.id = O.object_id where C.text like '%table_name%' 

Answer 6

原始问题要求将所有外键的列表放入高度引用的表中，以便可以删除该表。

这个小查询返回将所有外键放到特定表中所需的所有“外键”命令：

 SELECT 'ALTER TABLE ['+sch.name+'].['+referencingTable.Name+'] DROP CONSTRAINT ['+foreignKey.name+']' '[DropCommand]' FROM sys.foreign_key_columns fk JOIN sys.tables referencingTable ON fk.parent_object_id = referencingTable.object_id JOIN sys.schemas sch ON referencingTable.schema_id = sch.schema_id JOIN sys.objects foreignKey ON foreignKey.object_id = fk.constraint_object_id JOIN sys.tables referencedTable ON fk.referenced_object_id = referencedTable.object_id WHERE referencedTable.name = 'MyTableName' 

示例输出：

 [DropCommand] ALTER TABLE [dbo].[OtherTable1] DROP CONSTRAINT [FK_OtherTable1_MyTable] ALTER TABLE [dbo].[OtherTable2] DROP CONSTRAINT [FK_OtherTable2_MyTable] 

省略WHERE子句以获取当前数据库中所有外键的删除命令。

Answer 7

 SELECT PKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), PKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O1.SCHEMA_ID)), PKTABLE_NAME = CONVERT(SYSNAME,O1.NAME), PKCOLUMN_NAME = CONVERT(SYSNAME,C1.NAME), FKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), FKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O2.SCHEMA_ID)), FKTABLE_NAME = CONVERT(SYSNAME,O2.NAME), FKCOLUMN_NAME = CONVERT(SYSNAME,C2.NAME), -- Force the column to be non-nullable (see SQL BU 325751) --KEY_SEQ = isnull(convert(smallint,k.constraint_column_id), sysconv(smallint,0)), UPDATE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsUpdateCascade') WHEN 1 THEN 0 ELSE 1 END), DELETE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsDeleteCascade') WHEN 1 THEN 0 ELSE 1 END), FK_NAME = CONVERT(SYSNAME,OBJECT_NAME(F.OBJECT_ID)), PK_NAME = CONVERT(SYSNAME,I.NAME), DEFERRABILITY = CONVERT(SMALLINT,7) -- SQL_NOT_DEFERRABLE FROM SYS.ALL_OBJECTS O1, SYS.ALL_OBJECTS O2, SYS.ALL_COLUMNS C1, SYS.ALL_COLUMNS C2, SYS.FOREIGN_KEYS F INNER JOIN SYS.FOREIGN_KEY_COLUMNS K ON (K.CONSTRAINT_OBJECT_ID = F.OBJECT_ID) INNER JOIN SYS.INDEXES I ON (F.REFERENCED_OBJECT_ID = I.OBJECT_ID AND F.KEY_INDEX_ID = I.INDEX_ID) WHERE O1.OBJECT_ID = F.REFERENCED_OBJECT_ID AND O2.OBJECT_ID = F.PARENT_OBJECT_ID AND C1.OBJECT_ID = F.REFERENCED_OBJECT_ID AND C2.OBJECT_ID = F.PARENT_OBJECT_ID AND C1.COLUMN_ID = K.REFERENCED_COLUMN_ID AND C2.COLUMN_ID = K.PARENT_COLUMN_ID 

Answer 8

 SELECT object_name(parent_object_id), object_name(referenced_object_id), name FROM sys.foreign_keys WHERE parent_object_id = object_id('Table Name') 

Answer 9

请参阅如何编写表格的所有外键以获得帮助。

更新 ：链接不再可用，但相关的SQL被复制为相关问题的答案 。

您也可以通过GUI查看依赖关系。

Answer 10

我正在使用此脚本查找与外键相关的所有详细信息。 我正在使用INFORMATION.SCHEMA。 下面是一个SQL脚本：

 SELECT ccu.table_name AS SourceTable ,ccu.constraint_name AS SourceConstraint ,ccu.column_name AS SourceColumn ,kcu.table_name AS TargetTable ,kcu.column_name AS TargetColumn FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE ccu INNER JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS rc ON ccu.CONSTRAINT_NAME = rc.CONSTRAINT_NAME INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE kcu ON kcu.CONSTRAINT_NAME = rc.UNIQUE_CONSTRAINT_NAME ORDER BY ccu.table_name 

Answer 11

这是我将使用的SQL代码。

 SELECT f.name AS 'Name of Foreign Key', OBJECT_NAME(f.parent_object_id) AS 'Table name', COL_NAME(fc.parent_object_id,fc.parent_column_id) AS 'Fieldname', OBJECT_NAME(t.object_id) AS 'References Table name', COL_NAME(t.object_id,fc.referenced_column_id) AS 'References fieldname', 'ALTER TABLE [' + OBJECT_NAME(f.parent_object_id) + '] DROP CONSTRAINT [' + f.name + ']' AS 'Delete foreign key', 'ALTER TABLE [' + OBJECT_NAME(f.parent_object_id) + '] WITH NOCHECK ADD CONSTRAINT [' + f.name + '] FOREIGN KEY([' + COL_NAME(fc.parent_object_id,fc.parent_column_id) + ']) REFERENCES ' + '[' + OBJECT_NAME(t.object_id) + '] ([' + COL_NAME(t.object_id,fc.referenced_column_id) + '])' AS 'Create foreign key' -- , delete_referential_action_desc AS 'UsesCascadeDelete' FROM sys.foreign_keys AS f, sys.foreign_key_columns AS fc, sys.tables t WHERE f.OBJECT_ID = fc.constraint_object_id AND t.OBJECT_ID = fc.referenced_object_id AND OBJECT_NAME(t.object_id) = 'Employees' -- Just show the FKs which reference a particular table ORDER BY 2 

这不是特别清楚的SQL，所以我们来看一个例子。

所以，假设我想把Employees表放到微软喜欢的Northwind数据库中，但SQL Server告诉我一个或多个外键阻止了我这样做。

上面的SQL命令将返回这些结果…

它显示我有3个引用Employees表的外键。 换句话说，我将不允许删除（删除）这个表，直到这三个外键首先被删除。

在结果中，第一行是如何在结果中显示以下外键约束。

 ALTER TABLE [dbo].[Employees] WITH NOCHECK ADD CONSTRAINT [FK_Employees_Employees] FOREIGN KEY([ReportsTo]) REFERENCES [dbo].[Employees] ([EmployeeID]) 

倒数第二列显示了我需要用来删除这些外键之一的SQL命令，例如：

 ALTER TABLE [Employees] DROP CONSTRAINT [FK_Employees_Employees] 

…右侧的列显示了SQL来创建它…

 ALTER TABLE [Employees] WITH NOCHECK ADD CONSTRAINT [FK_Employees_Employees] FOREIGN KEY([ReportsTo]) REFERENCES [Employees] ([EmployeeID]) 

通过所有这些命令，您可以拥有删除相关外键所需的所有内容，以便删除表，然后重新创建它们。

唷。 希望这可以帮助。

Answer 12

上面的一些好的答案。 但我更喜欢有一个查询的答案。 这段代码取自sys.sp_helpconstraint（sys proc）

这是微软查找的方式，如果有外键关联到TBL。

 --setup variables. Just change 'Customer' to tbl you want declare @objid int, @objname nvarchar(776) select @objname = 'Customer' select @objid = object_id(@objname) if exists (select * from sys.foreign_keys where referenced_object_id = @objid) select 'Table is referenced by foreign key' = db_name() + '.' + rtrim(schema_name(ObjectProperty(parent_object_id,'schemaid'))) + '.' + object_name(parent_object_id) + ': ' + object_name(object_id) from sys.foreign_keys where referenced_object_id = @objid order by 1 

答案将如下所示：test_db_name.dbo.Account：FK_Account_Customer

Answer 13

  SELECT OBJECT_NAME(fk.parent_object_id) as ReferencingTable, OBJECT_NAME(fk.constraint_object_id) as [FKContraint] FROM sys.foreign_key_columns as fk WHERE fk.referenced_object_id = OBJECT_ID('ReferencedTable', 'U') 

这只显示了如果是外键约束的关系。 我的数据库显然早于FK约束。有些表使用触发器来强制引用完整性，有时候只有一个类似命名的列来指示关系（并且根本没有参照完整性）。

幸运的是，我们有一个一致的命名场景，所以我能够找到像这样的引用表和视图：

 SELECT OBJECT_NAME(object_id) from sys.columns where name like 'client_id' 

我用这个选择作为生成一个脚本的基础，做我需要做的相关表。

Answer 14

 SELECT OBJECT_NAME(parent_object_id) 'Parent table', c.NAME 'Parent column name', OBJECT_NAME(referenced_object_id) 'Referenced table', cref.NAME 'Referenced column name' FROM sys.foreign_key_columns fkc INNER JOIN sys.columns c ON fkc.parent_column_id = c.column_id AND fkc.parent_object_id = c.object_id INNER JOIN sys.columns cref ON fkc.referenced_column_id = cref.column_id AND fkc.referenced_object_id = cref.object_id where OBJECT_NAME(parent_object_id) = 'tablename' 

如果你想获得所有表的外键关系，排除where子句写你的表名而不是tablename

Answer 15

根据@Gishu所做的工作，我能够在SQL Server 2005中生成和使用以下SQL

 SELECT t.name AS TableWithForeignKey, fk.constraint_column_id AS FK_PartNo, c.name AS ForeignKeyColumn, o.name AS FK_Name FROM sys.foreign_key_columns AS fk INNER JOIN sys.tables AS t ON fk.parent_object_id = t.object_id INNER JOIN sys.columns AS c ON fk.parent_object_id = c.object_id AND fk.parent_column_id = c.column_id INNER JOIN sys.objects AS o ON fk.constraint_object_id = o.object_id WHERE fk.referenced_object_id = (SELECT object_id FROM sys.tables WHERE name = 'TableOthersForeignKeyInto') ORDER BY TableWithForeignKey, FK_PartNo; 

其中在1查询中显示表，列和外键名称。

Answer 16

确定数据库中所有表的主键和唯一键…

这应该列出所有的限制，最后你可以把你的过滤器

 /* CAST IS DONE , SO THAT OUTPUT INTEXT FILE REMAINS WITH SCREEN LIMIT*/ WITH ALL_KEYS_IN_TABLE (CONSTRAINT_NAME,CONSTRAINT_TYPE,PARENT_TABLE_NAME,PARENT_COL_NAME,PARENT_COL_NAME_DATA_TYPE,REFERENCE_TABLE_NAME,REFERENCE_COL_NAME) AS ( SELECT CONSTRAINT_NAME= CAST (PKnUKEY.name AS VARCHAR(30)) , CONSTRAINT_TYPE=CAST (PKnUKEY.type_desc AS VARCHAR(30)) , PARENT_TABLE_NAME=CAST (PKnUTable.name AS VARCHAR(30)) , PARENT_COL_NAME=CAST ( PKnUKEYCol.name AS VARCHAR(30)) , PARENT_COL_NAME_DATA_TYPE= oParentColDtl.DATA_TYPE, REFERENCE_TABLE_NAME='' , REFERENCE_COL_NAME='' FROM sys.key_constraints as PKnUKEY INNER JOIN sys.tables as PKnUTable ON PKnUTable.object_id = PKnUKEY.parent_object_id INNER JOIN sys.index_columns as PKnUColIdx ON PKnUColIdx.object_id = PKnUTable.object_id AND PKnUColIdx.index_id = PKnUKEY.unique_index_id INNER JOIN sys.columns as PKnUKEYCol ON PKnUKEYCol.object_id = PKnUTable.object_id AND PKnUKEYCol.column_id = PKnUColIdx.column_id INNER JOIN INFORMATION_SCHEMA.COLUMNS oParentColDtl ON oParentColDtl.TABLE_NAME=PKnUTable.name AND oParentColDtl.COLUMN_NAME=PKnUKEYCol.name UNION ALL SELECT CONSTRAINT_NAME= CAST (oConstraint.name AS VARCHAR(30)) , CONSTRAINT_TYPE='FK', PARENT_TABLE_NAME=CAST (oParent.name AS VARCHAR(30)) , PARENT_COL_NAME=CAST ( oParentCol.name AS VARCHAR(30)) , PARENT_COL_NAME_DATA_TYPE= oParentColDtl.DATA_TYPE, REFERENCE_TABLE_NAME=CAST ( oReference.name AS VARCHAR(30)) , REFERENCE_COL_NAME=CAST (oReferenceCol.name AS VARCHAR(30)) FROM sys.foreign_key_columns FKC INNER JOIN sys.sysobjects oConstraint ON FKC.constraint_object_id=oConstraint.id INNER JOIN sys.sysobjects oParent ON FKC.parent_object_id=oParent.id INNER JOIN sys.all_columns oParentCol ON FKC.parent_object_id=oParentCol.object_id /* ID of the object to which this column belongs.*/ AND FKC.parent_column_id=oParentCol.column_id/* ID of the column. Is unique within the object.Column IDs might not be sequential.*/ INNER JOIN sys.sysobjects oReference ON FKC.referenced_object_id=oReference.id INNER JOIN INFORMATION_SCHEMA.COLUMNS oParentColDtl ON oParentColDtl.TABLE_NAME=oParent.name AND oParentColDtl.COLUMN_NAME=oParentCol.name INNER JOIN sys.all_columns oReferenceCol ON FKC.referenced_object_id=oReferenceCol.object_id /* ID of the object to which this column belongs.*/ AND FKC.referenced_column_id=oReferenceCol.column_id/* ID of the column. Is unique within the object.Column IDs might not be sequential.*/ ) select * from ALL_KEYS_IN_TABLE where PARENT_TABLE_NAME in ('YOUR_TABLE_NAME') or REFERENCE_TABLE_NAME in ('YOUR_TABLE_NAME') ORDER BY PARENT_TABLE_NAME,CONSTRAINT_NAME; 

有关参考请阅读 – http://blogs.msdn.com/b/sqltips/archive/2005/09/16/469136.aspx

Answer 17

我一直在使用这个在2008年以后。 它与列出的一些其他解决方案类似，但是，字段名称适合于处理特定于案例（LatBin）的归类。 另外，您可以为它提供一个表名，并只检索该表的信息。

 -->>SPECIFY THE DESIRED DB USE ??? GO /********************************************************************************************* LIST OUT ALL PRIMARY AND FOREIGN KEY CONSTRAINTS IN A DB OR FOR A SPECIFIED TABLE *********************************************************************************************/ DECLARE @tblName VARCHAR(255) /*******************/ SET @tblName = NULL-->NULL will return all PK/FK constraints for every table in the database /*******************/ SELECT PKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), PKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O1.schema_id)), PKTABLE_NAME = CONVERT(SYSNAME,O1.name), PKCOLUMN_NAME = CONVERT(SYSNAME,C1.name), FKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), FKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O2.schema_id)), FKTABLE_NAME = CONVERT(SYSNAME,O2.name), FKCOLUMN_NAME = CONVERT(SYSNAME,C2.name), -- Force the column to be non-nullable (see SQL BU 325751) KEY_SEQ = isnull(convert(smallint,K.constraint_column_id),0), UPDATE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.object_id,'CnstIsUpdateCascade') WHEN 1 THEN 0 ELSE 1 END), DELETE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.object_id,'CnstIsDeleteCascade') WHEN 1 THEN 0 ELSE 1 END), FK_NAME = CONVERT(SYSNAME,OBJECT_NAME(F.object_id)), PK_NAME = CONVERT(SYSNAME,I.name), DEFERRABILITY = CONVERT(SMALLINT,7) -- SQL_NOT_DEFERRABLE FROM sys.all_objects O1, sys.all_objects O2, sys.all_columns C1, sys.all_columns C2, sys.foreign_keys F INNER JOIN sys.foreign_key_columns K ON (K.constraint_object_id = F.object_id) INNER JOIN sys.indexes I ON (F.referenced_object_id = I.object_id AND F.key_index_id = I.index_id) WHERE O1.object_id = F.referenced_object_id AND O2.object_id = F.parent_object_id AND C1.object_id = F.referenced_object_id AND C2.object_id = F.parent_object_id AND C1.column_id = K.referenced_column_id AND C2.column_id = K.parent_column_id AND ( O1.name = @tblName OR O2.name = @tblName OR @tblName IS null) ORDER BY PKTABLE_NAME,FKTABLE_NAME 

Answer 18

有如何获得选定的Id的所有责任计数。 只需更改@dbTableName值，@dbRowId值及其类型（如果int需要在第82行（..SET @SQL = ..）中删除''）。 请享用。

 DECLARE @dbTableName varchar(max) = 'User' DECLARE @dbRowId uniqueidentifier = '21d34ecd-c1fd-11e2-8545-002219a42e1c' DECLARE @FK_ROWCOUNT int DECLARE @SQL nvarchar(max) DECLARE @PKTABLE_QUALIFIER sysname DECLARE @PKTABLE_OWNER sysname DECLARE @PKTABLE_NAME sysname DECLARE @PKCOLUMN_NAME sysname DECLARE @FKTABLE_QUALIFIER sysname DECLARE @FKTABLE_OWNER sysname DECLARE @FKTABLE_NAME sysname DECLARE @FKCOLUMN_NAME sysname DECLARE @UPDATE_RULE smallint DECLARE @DELETE_RULE smallint DECLARE @FK_NAME sysname DECLARE @PK_NAME sysname DECLARE @DEFERRABILITY sysname IF OBJECT_ID('tempdb..#Temp1') IS NOT NULL DROP TABLE #Temp1; CREATE TABLE #Temp1 ( PKTABLE_QUALIFIER sysname, PKTABLE_OWNER sysname, PKTABLE_NAME sysname, PKCOLUMN_NAME sysname, FKTABLE_QUALIFIER sysname, FKTABLE_OWNER sysname, FKTABLE_NAME sysname, FKCOLUMN_NAME sysname, UPDATE_RULE smallint, DELETE_RULE smallint, FK_NAME sysname, PK_NAME sysname, DEFERRABILITY sysname, FK_ROWCOUNT int ); DECLARE FK_Counter_Cursor CURSOR FOR SELECT PKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), PKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O1.SCHEMA_ID)), PKTABLE_NAME = CONVERT(SYSNAME,O1.NAME), PKCOLUMN_NAME = CONVERT(SYSNAME,C1.NAME), FKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), FKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O2.SCHEMA_ID)), FKTABLE_NAME = CONVERT(SYSNAME,O2.NAME), FKCOLUMN_NAME = CONVERT(SYSNAME,C2.NAME), -- Force the column to be non-nullable (see SQL BU 325751) --KEY_SEQ = isnull(convert(smallint,k.constraint_column_id), sysconv(smallint,0)), UPDATE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsUpdateCascade') WHEN 1 THEN 0 ELSE 1 END), DELETE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsDeleteCascade') WHEN 1 THEN 0 ELSE 1 END), FK_NAME = CONVERT(SYSNAME,OBJECT_NAME(F.OBJECT_ID)), PK_NAME = CONVERT(SYSNAME,I.NAME), DEFERRABILITY = CONVERT(SMALLINT,7) -- SQL_NOT_DEFERRABLE FROM SYS.ALL_OBJECTS O1, SYS.ALL_OBJECTS O2, SYS.ALL_COLUMNS C1, SYS.ALL_COLUMNS C2, SYS.FOREIGN_KEYS F INNER JOIN SYS.FOREIGN_KEY_COLUMNS K ON (K.CONSTRAINT_OBJECT_ID = F.OBJECT_ID) INNER JOIN SYS.INDEXES I ON (F.REFERENCED_OBJECT_ID = I.OBJECT_ID AND F.KEY_INDEX_ID = I.INDEX_ID) WHERE O1.OBJECT_ID = F.REFERENCED_OBJECT_ID AND O2.OBJECT_ID = F.PARENT_OBJECT_ID AND C1.OBJECT_ID = F.REFERENCED_OBJECT_ID AND C2.OBJECT_ID = F.PARENT_OBJECT_ID AND C1.COLUMN_ID = K.REFERENCED_COLUMN_ID AND C2.COLUMN_ID = K.PARENT_COLUMN_ID AND O1.NAME = @dbTableName OPEN FK_Counter_Cursor; FETCH NEXT FROM FK_Counter_Cursor INTO @PKTABLE_QUALIFIER, @PKTABLE_OWNER, @PKTABLE_NAME, @PKCOLUMN_NAME, @FKTABLE_QUALIFIER, @FKTABLE_OWNER, @FKTABLE_NAME, @FKCOLUMN_NAME, @UPDATE_RULE, @DELETE_RULE, @FK_NAME, @PK_NAME, @DEFERRABILITY; WHILE @@FETCH_STATUS = 0 BEGIN SET @SQL = 'SELECT @dbCountOut = COUNT(*) FROM [' + @FKTABLE_NAME + '] WHERE [' + @FKCOLUMN_NAME + '] = ''' + CAST(@dbRowId AS varchar(max)) + ''''; EXECUTE sp_executesql @SQL, N'@dbCountOut int OUTPUT', @dbCountOut = @FK_ROWCOUNT OUTPUT; INSERT INTO #Temp1 (PKTABLE_QUALIFIER, PKTABLE_OWNER, PKTABLE_NAME, PKCOLUMN_NAME, FKTABLE_QUALIFIER, FKTABLE_OWNER, FKTABLE_NAME, FKCOLUMN_NAME, UPDATE_RULE, DELETE_RULE, FK_NAME, PK_NAME, DEFERRABILITY, FK_ROWCOUNT) VALUES (@FKTABLE_QUALIFIER, @PKTABLE_OWNER, @PKTABLE_NAME, @PKCOLUMN_NAME, @FKTABLE_QUALIFIER, @FKTABLE_OWNER, @FKTABLE_NAME, @FKCOLUMN_NAME, @UPDATE_RULE, @DELETE_RULE, @FK_NAME, @PK_NAME, @DEFERRABILITY, @FK_ROWCOUNT) FETCH NEXT FROM FK_Counter_Cursor INTO @PKTABLE_QUALIFIER, @PKTABLE_OWNER, @PKTABLE_NAME, @PKCOLUMN_NAME, @FKTABLE_QUALIFIER, @FKTABLE_OWNER, @FKTABLE_NAME, @FKCOLUMN_NAME, @UPDATE_RULE, @DELETE_RULE, @FK_NAME, @PK_NAME, @DEFERRABILITY; END; CLOSE FK_Counter_Cursor; DEALLOCATE FK_Counter_Cursor; GO SELECT * FROM #Temp1 GO 

Answer 19

这将获得涉及所选表的任何外键。 *假设一个_FIRSTABLENAME_SECONDTABLENAME格式。

  declare @tablename as varchar(MAX) SET @tablename = 'yourtablename' SELECT name FROM YOURDATABASE.sys.objects WHERE type_desc = 'FOREIGN_KEY_CONSTRAINT' and (name LIKE '%_' + @tablename + 'empdb_%' or name LIKE '%_' + @tablename ) 

这是一个更一般的形式：

  SELECT name FROM YOURDATABASE_PROD.sys.objects WHERE type_desc = 'FOREIGN_KEY_CONSTRAINT' and name LIKE '%' + @tablename + '%' and name NOT LIKE '[a-zA-Z0-9]' + @tablename + '%' and name NOT LIKE '%' + @tablename + '[a-zA-Z0-9]' 

Answer 20

第一

 EXEC sp_fkeys 'Table', 'Schema' 

然后使用NimbleText玩你的结果