在Serializable C＃类中使用不带XmlArray的XmlArrayItem属性
我想用以下格式的XML：
<configuration><!-- Only one configuration node --> <logging>...</logging><!-- Only one logging node --> <credentials>...</credentials><!-- One or more credentials nodes --> <credentials>...</credentials> </configuration> 我想创build一个具有[Serializable]属性的类Configuration 。 要序列化凭证节点，我有以下几点：
[XmlArray("configuration")] [XmlArrayItem("credentials", typeof(CredentialsSection))] public List<CredentialsSection> Credentials { get; set; }
但是，当我将它序列化为XML时，XML格式如下：
<configuration> <logging>...</logging> <configuration><!-- Don't want credentials nodes nested in a second configuration node --> <credentials>...</credentials> <credentials>...</credentials> </configuration> </configuration>
如果我删除[XmlArray("configuration")]行，我得到以下内容：
<configuration> <logging>...</logging> <Credentials><!-- Don't want credentials nodes nested in Credentials node --> <credentials>...</credentials> <credentials>...</credentials> </Credentials> </configuration>
我怎样才能以我想要的方式序列化这个，在单根节点<configuration>有多个<credentials>节点？ 我想这样做，而不必实现IXmlSerializable和自定义序列化。 这就是我的class级的描述：
[Serializable] [XmlRoot("configuration")] public class Configuration : IEquatable<Configuration>
以下应该按照你想要的方式正确地序列化。 线索是列表上的[XmlElement("credentials")] 。 我通过采取你的xml，在Visual Studio中从它生成一个模式（xsd）。 然后在模式上运行xsd.exe以生成一个类。 （和一些小编辑）
public class CredentialsSection { public string Username { get; set; } public string Password { get; set; } } [XmlRoot(Namespace = "", IsNullable = false)] public class configuration { /// <remarks/> public string logging { get; set; } /// <remarks/> [XmlElement("credentials")] public List<CredentialsSection> credentials { get; set; } public string Serialize() { var credentialsSection = new CredentialsSection {Username = "a", Password = "b"}; this.credentials = new List<CredentialsSection> {credentialsSection, credentialsSection}; this.logging = "log this"; XmlSerializer s = new XmlSerializer(this.GetType()); StringBuilder sb = new StringBuilder(); TextWriter w = new StringWriter(sb); s.Serialize(w, this); w.Flush(); return sb.ToString(); } }
给出以下输出
<?xml version="1.0" encoding="utf-16"?> <configuration xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <logging>log this</logging> <credentials> <Username>a</Username> <Password>b</Password> </credentials> <credentials> <Username>a</Username> <Password>b</Password> </credentials> </configuration>
