在Ruby on Rails中将DateTime转换为简单的date
我有一个date时间列的数据库，我想变成一个简单的date，当我展示给用户。
我怎样才能做到这一点？
def shown_date ＃to_date不存在，但是我正在寻找 self.date || self.exif_date_time_original.to_date 结束
DateTime#to_date确实存在与ActiveSupport：
$ irb >> DateTime.new.to_date NoMethodError: undefined method 'to_date' for #<DateTime: -1/2,0,2299161> from (irb):1 >> require 'active_support/core_ext' => true >> DateTime.new.to_date => Mon, 01 Jan -4712
你好collimarco :)你可以使用ruby strftime方法来创build你自己的date/时间显示。
time.strftime（string）=> string
%a - The abbreviated weekday name (``Sun'') %A - The full weekday name (``Sunday'') %b - The abbreviated month name (``Jan'') %B - The full month name (``January'') %c - The preferred local date and time representation %d - Day of the month (01..31) %H - Hour of the day, 24-hour clock (00..23) %I - Hour of the day, 12-hour clock (01..12) %j - Day of the year (001..366) %m - Month of the year (01..12) %M - Minute of the hour (00..59) %p - Meridian indicator (``AM'' or ``PM'') %S - Second of the minute (00..60) %U - Week number of the current year, starting with the first Sunday as the first day of the first week (00..53) %W - Week number of the current year, starting with the first Monday as the first day of the first week (00..53) %w - Day of the week (Sunday is 0, 0..6) %x - Preferred representation for the date alone, no time %X - Preferred representation for the time alone, no date %y - Year without a century (00..99) %Y - Year with century %Z - Time zone name %% - Literal ``%'' character t = Time.now t.strftime("Printed on %m/%d/%Y") #=> "Printed on 04/09/2003" t.strftime("at %I:%M%p") #=> "at 08:56AM"
在Ruby 1.9.2及以上版本中，他们向DateTime添加了一个.to_date函数：
http://ruby-doc.org/stdlib-1.9.2/libdoc/date/rdoc/DateTime.html#method-i-to_date
这个实例方法在1.8.7之类的早期版本中似乎不存在。
我最近写了一个gem来简化这个过程，并且整理你的观点等等。
查看： http ： //github.com/platform45/easy_dates
尝试先将条目转换为string。 只要数据库的列types是一个date，它将被格式化为一个date。
self.date || self.exif_date_time_original.to_s
对于旧的Ruby（1.8.x）：
myDate = Date.parse(myDateTime.to_s)
