POST请求与JSON正文
我想通过PHP将博文添加到Blogger博客 。 Google提供了下面的例子。 如何使用PHP？
您可以通过发送POST请求到后期收集URI和后期JSON主体来为博客添加一篇文章：
POST https://www.googleapis.com/blogger/v3/blogs/8070105920543249955/posts/ Authorization: /* OAuth 2.0 token here */ Content-Type: application/json { "kind": "blogger#post", "blog": { "id": "8070105920543249955" }, "title": "A new post", "content": "With <b>exciting</b> content..." } 你需要使用cURL库来发送这个请求。
<?php // Your ID and token $blogID = '8070105920543249955'; $authToken = 'OAuth 2.0 token here'; // The data to send to the API $postData = array( 'kind' => 'blogger#post', 'blog' => array('id' => $blogID), 'title' => 'A new post', 'content' => 'With <b>exciting</b> content...' ); // Setup cURL $ch = curl_init('https://www.googleapis.com/blogger/v3/blogs/'.$blogID.'/posts/'); curl_setopt_array($ch, array( CURLOPT_POST => TRUE, CURLOPT_RETURNTRANSFER => TRUE, CURLOPT_HTTPHEADER => array( 'Authorization: '.$authToken, 'Content-Type: application/json' ), CURLOPT_POSTFIELDS => json_encode($postData) )); // Send the request $response = curl_exec($ch); // Check for errors if($response === FALSE){ die(curl_error($ch)); } // Decode the response $responseData = json_decode($response, TRUE); // Print the date from the response echo $responseData['published'];
如果由于某种原因，你不能/不想用cURL，你可以这样做：
<?php // Your ID and token $blogID = '8070105920543249955'; $authToken = 'OAuth 2.0 token here'; // The data to send to the API $postData = array( 'kind' => 'blogger#post', 'blog' => array('id' => $blogID), 'title' => 'A new post', 'content' => 'With <b>exciting</b> content...' ); // Create the context for the request $context = stream_context_create(array( 'http' => array( // http://www.php.net/manual/en/context.http.php 'method' => 'POST', 'header' => "Authorization: {$authToken}\r\n". "Content-Type: application/json\r\n", 'content' => json_encode($postData) ) )); // Send the request $response = file_get_contents('https://www.googleapis.com/blogger/v3/blogs/'.$blogID.'/posts/', FALSE, $context); // Check for errors if($response === FALSE){ die('Error'); } // Decode the response $responseData = json_decode($response, TRUE); // Print the date from the response echo $responseData['published'];
我认为cURL将是一个很好的解决scheme。 这没有testing，但你可以尝试这样的事情：
$body = '{ "kind": "blogger#post", "blog": { "id": "8070105920543249955" }, "title": "A new post", "content": "With <b>exciting</b> content..." }'; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "https://www.googleapis.com/blogger/v3/blogs/8070105920543249955/posts/"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: application/json","Authorization: OAuth 2.0 token here")); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $body); $result = curl_exec($ch);
如果你不想使用CURL，你可以在这里find一些关于stackoverflow的例子： 如何用PHP发送POST请求？ 。 我build议你看看如何在PHP中使用GET和POST方法的几个教程，或者看看这里的php.net手册： httprequest :: send 。 你可以find很多的教程： 来自PHP的HTTP POST，没有cURL等等…
<?php // Example API call $data = array(array ( "REGION" => "MUMBAI", "LOCATION" => "NA", "STORE" => "AMAZON")); // json encode data $authToken = "xxxxxxxxxx"; $data_string = json_encode($data); // set up the curl resource $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://domainyouhaveapi.com"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string); curl_setopt($ch, CURLOPT_HEADER, true); curl_setopt($ch, CURLOPT_HTTPHEADER, array( 'Content-Type:application/json', 'Content-Length: ' . strlen($data_string) , 'API-TOKEN-KEY:'.$authToken )); // API-TOKEN-KEY is keyword so change according to ur key word. like authorization // execute the request $output = curl_exec($ch); //echo $output; // Check for errors if($output === FALSE){ die(curl_error($ch)); } echo($output) . PHP_EOL; // close curl resource to free up system resources curl_close($ch);
我使用@Rocket Hazmat，@ dbau和@maraca代码，通过网站上的表单将API发送数据发送到prosperworks。 我希望，这将有助于某人：
<?php if(isset($_POST['submit'])) { //form's fields name: $name = $_POST['nameField']; $email = $_POST['emailField']; //API url: $url = 'https://api.prosperworks.com/developer_api/v1/leads'; //JSON data(not exact, but will be compiled to JSON) file: //add as many data as you need (according to prosperworks doc): $data = array( 'name' => $name, 'email' => array('email' => $email) ); //sending request (according to prosperworks documentation): // use key 'http' even if you send the request to https://... $options = array( 'http' => array( 'header' => "Content-Type: application/json\r\n". "X-PW-AccessToken: YOUR_TOKEN_HERE\r\n". "X-PW-Application:developer_api\r\n". "X-PW-UserEmail: YOUR_EMAIL_HERE\r\n", 'method' => 'POST', 'content' => json_encode($data) ) ); //engine: $context = stream_context_create($options); $result = file_get_contents($url, false, $context); if ($result === FALSE) { /* Handle error */ } //compiling to JSON (as wrote above): $resultData = json_decode($result, TRUE); //display what was sent: echo '<h2>Sent: </h2>'; echo $resultData['published']; //dump var: var_dump($result); } ?> <html> <head> </head> <body> <form action="" method="POST"> <h1><?php echo $msg; ?></h1> Name: <input type="text" name="nameField"/> <br> Email: <input type="text" name="emailField"/> <input type="submit" name="submit" value="Send"/> </form> </body> </html>
