检测NSString是否包含…？
如何检测string是否包含某个单词？ 例如，我有一个string下面写着：
@"Here is my string." 我想知道是否可以检测string中的单词，例如“is”。
以下是我将如何做到这一点：
NSString *someString = @"Here is my string"; NSRange isRange = [someString rangeOfString:@"is " options:NSCaseInsensitiveSearch]; if(isRange.location == 0) { //found it... } else { NSRange isSpacedRange = [someString rangeOfString:@" is " options:NSCaseInsensitiveSearch]; if(isSpacedRange.location != NSNotFound) { //found it... } }
你可以很容易地把它作为一个类别添加到NSString ：
@interface NSString (JRStringAdditions) - (BOOL)containsString:(NSString *)string; - (BOOL)containsString:(NSString *)string options:(NSStringCompareOptions)options; @end @implementation NSString (JRStringAdditions) - (BOOL)containsString:(NSString *)string options:(NSStringCompareOptions)options { NSRange rng = [self rangeOfString:string options:options]; return rng.location != NSNotFound; } - (BOOL)containsString:(NSString *)string { return [self containsString:string options:0]; } @end
使用下面的代码扫描句子中的单词。
NSString *sentence = @"The quick brown fox"; NSString *word = @"quack"; if ([sentence rangeOfString:word].location != NSNotFound) { NSLog(@"Yes it does contain that word"); }
在iOS8中，您现在可以使用：
BOOL containsString = [@"Here is my string." containsString:@"is"];
这里有一个有趣的post，告诉你如何在iOS7上“改造”它： http ://petersteinberger.com/blog/2014/retrofitting-containsstring-on-ios-7/
我希望这可以帮助你，..在.m文件添加此行或创build一个单独的类，并整合此代码。
@implementation NSString (Contains) - (BOOL) containsString: (NSString*) substring { NSRange range = [self rangeOfString : substring]; BOOL found = ( range.location != NSNotFound ); return found; } @end
我build议使用NSLinguisticTagger 。 我们可以用它来searchHere is my string. His isn't a mississippi isthmus. It is? Here is my string. His isn't a mississippi isthmus. It is?
NSLinguisticTagger *linguisticTagger = [[NSLinguisticTagger alloc] initWithTagSchemes:@[ NSLinguisticTagSchemeTokenType, ] options: NSLinguisticTaggerOmitPunctuation | NSLinguisticTaggerOmitWhitespace | NSLinguisticTaggerOmitOther ]; [linguisticTagger setString:@"Here is my string. His isn't a mississippi isthmus. It is?"]; [linguisticTagger enumerateTagsInRange:NSMakeRange(0, [[linguisticTagger string] length]) scheme:NSLinguisticTagSchemeTokenType options: NSLinguisticTaggerOmitPunctuation | NSLinguisticTaggerOmitWhitespace | NSLinguisticTaggerOmitOther | NSLinguisticTaggerJoinNames usingBlock:^(NSString *tag, NSRange tokenRange, NSRange sentenceRange, BOOL *stop) { NSLog(@"tag: %@, tokenRange: %@, sentenceRange: %@, token: %@", tag, NSStringFromRange(tokenRange), NSStringFromRange(sentenceRange), [[linguisticTagger string] substringWithRange:tokenRange]); }];
这输出：
tag: Word, tokenRange: {0, 4}, sentenceRange: {0, 19}, token: Here tag: Word, tokenRange: {5, 2}, sentenceRange: {0, 19}, token: is tag: Word, tokenRange: {8, 2}, sentenceRange: {0, 19}, token: my tag: Word, tokenRange: {11, 6}, sentenceRange: {0, 19}, token: string tag: Word, tokenRange: {19, 3}, sentenceRange: {19, 33}, token: His tag: Word, tokenRange: {23, 2}, sentenceRange: {19, 33}, token: is tag: Word, tokenRange: {25, 3}, sentenceRange: {19, 33}, token: n't tag: Word, tokenRange: {29, 1}, sentenceRange: {19, 33}, token: a tag: Word, tokenRange: {31, 11}, sentenceRange: {19, 33}, token: mississippi tag: Word, tokenRange: {43, 7}, sentenceRange: {19, 33}, token: isthmus tag: Word, tokenRange: {52, 2}, sentenceRange: {52, 6}, token: It tag: Word, tokenRange: {55, 2}, sentenceRange: {52, 6}, token: is
它忽略了His mississippi和isthmus ，甚至认定isn't 。
使用iOS 8和Swift，我们可以使用localizedCaseInsensitiveContainsString方法
let string: NSString = "Café" let substring: NSString = "É" string.localizedCaseInsensitiveContainsString(substring) // true
一个完整的解决scheme将首先扫描string（不添加空格），然后检查前面的字符是空白还是行尾。 同样，检查紧接着的字符是空白还是行尾。 如果两项testing都通过，那么你有一场比赛。 根据你的需要，你也可以检查， . ， ()等
当然，另一种方法是将stringparsing为单词并单独检查每个单词。
