mysqli_select_db()期望参数1是mysqli,给出的string
可能重复:
mysql_fetch_array()期望参数1是资源,布尔在select中给出
我是Mysqli_ *的新手,我收到这些错误:
警告:mysqli_select_db()期望参数1是mysqli,在第11行D:\ Hosting \ 9864230 \ html \ includes \ connection.php中给出的string
警告:mysqli_error()需要在第13行D:\ Hosting \ 9864230 \ html \ includes \ connection.php中给出的只有1个参数
数据库select失败:
<?php require("constants.php"); // 1. Create a database connection $connection = mysqli_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysqli_error()); } // 2. Select a database to use $db_select = mysqli_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysqli_error()); } ?>
你的论点是错误的。 根据文档 ,连接是第一位的
<?php require("constants.php"); // 1. Create a database connection $connection = mysqli_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysqli_error()); } // 2. Select a database to use $db_select = mysqli_select_db($connection, DB_NAME); if (!$db_select) { die("Database selection failed: " . mysqli_error()); } ?>
// 2. Select a database to use $db_select = mysqli_select_db($connection, DB_NAME); if (!$db_select) { die("Database selection failed: " . mysqli_error($connection)); }
你得到了mysqli_select_db()
的参数顺序。 而mysqli_error()
要求你提供一个连接参数。 mysqli_XXX不像mysql_XXX,这些参数不再是可选的。
还要注意,用mysqli你可以在mysqli_connect()
指定数据库:
$connection = mysqli_connect(DB_SERVER, DB_USER, DB_PASS, DB_NAME); if (!$connection) { die("Database connection failed: " . mysqli_connect_error(); }
您必须使用mysqli_connect_error()
而不是mysqli_error()
来从mysqli_connect()
获取错误,因为后者要求您提供有效的连接。