MySQL – 在WHERE子句中使用COUNT（*）

我正在尝试在MySQL中完成以下操作（请参阅pseudo代码）

 SELECT DISTINCT gid FROM `gd` WHERE COUNT(*) > 10 ORDER BY lastupdated DESC 

有没有办法做到这一点，而不是在WHERE子句中使用（SELECT …），因为这看起来像是浪费资源。

所有的帮助表示赞赏。

谢谢！

Answer 1

尝试这个;

 select gid from `gd` group by gid having count(*) > 10 order by lastupdated desc 

Answer 2

我不知道你在做什么…也许是这样的

 SELECT gid, COUNT(*) AS num FROM gd GROUP BY gid HAVING num > 10 ORDER BY lastupdated DESC 

Answer 3

尝试

 SELECT DISTINCT gid FROM `gd` group by gid having count(*) > 10 ORDER BY max(lastupdated) DESC 

Answer 4

 SELECT COUNT(*) FROM `gd` GROUP BY gid HAVING COUNT(gid) > 10 ORDER BY lastupdated DESC; 

编辑（如果你只是想要gids）：

 SELECT MIN(gid) FROM `gd` GROUP BY gid HAVING COUNT(gid) > 10 ORDER BY lastupdated DESC 

Answer 5

只是没有条款的学术版本：

 select * from ( select gid, count(*) as tmpcount from gd group by gid ) as tmp where tmpcount > 10; 

Answer 6

– search缺less半小时logging的气象站

 SELECT stationid FROM weather_data WHERE `Timestamp` LIKE '2011-11-15 %' AND stationid IN (SELECT `ID` FROM `weather_stations`) GROUP BY stationid HAVING COUNT(*) != 48; 

– yapiskan的变化与一个where .. in .. select

Answer 7

在WHERE子句中不能有聚合函数（例如COUNT，MAX等）。 因此我们使用HAVING子句。 因此，整个查询将类似于：

 SELECT column_name, aggregate_function(column_name) FROM table_name WHERE column_name operator value GROUP BY column_name HAVING aggregate_function(column_name) operator value; 

Answer 8

我认为你不能where添加count() 。 现在看到为什么….

having意思，就是说你在工作或者处理团队和统计工作，它也是处理整个团队的，

现在它是如何算作整个小组的工作

创build一个表并input一些id，然后使用：

 select count(*) from table_name 

你会发现总价值意味着它是指示一些组！ 所以where添加count() ;