mysql – 将行从一个表移动到另一个表

如果我有两个在结构上相同的表，我怎样才能从一个表中移动一组到另一个表？

这组行将从select查询中确定。

例如：

customer table person_id | person_name | person_email 123 tom [e-mail] persons table person_id | person_name | person_email 

样本select将是：

 select * from customer_table where person_name = 'tom'; 

我想从客户表格移动到人员表格

理想情况下，从原始表中删除数据，但这不会是一个交易断路器。

Answer 1

一个简单的INSERT INTO SELECT语句：

 INSERT INTO persons_table select * from customer_table where person_name = 'tom'; 

---

 DELETE FROM customer_table where person_name = 'tom'; 

Answer 2

  INSERT INTO Persons_Table (person_id, person_name,person_email) SELECT person_id, customer_name, customer_email FROM customer_table WHERE "insert your where clause here"; DELETE FROM customer_table WHERE "repeat your where clause here"; 

Answer 3

法比奥的答案确实不错，但需要很长的执行时间（正如Trilarion已经写过的那样）

我有一个更快的执行其他解决scheme。

 START TRANSACTION; set @N := (now()); INSERT INTO table2 select * from table1 where ts < date_sub(@N,INTERVAL 32 DAY); DELETE FROM table1 WHERE ts < date_sub(@N,INTERVAL 32 DAY); COMMIT; 

@N在开始时获得时间戳，并用于这两个命令。 一切都在交易中，以确保没有人感到困扰

Answer 4

 INSERT INTO Persons_Table (person_id, person_name,person_email) SELECT person_id, customer_name, customer_email FROM customer_table ORDER BY `person_id` DESC LIMIT 0, 15 WHERE "insert your where clause here"; DELETE FROM customer_table WHERE "repeat your where clause here"; 

您还可以使用ORDER BY，LIMIT和ASC / DESC来限制和select要移动的特定列。

Answer 5

我必须解决同样的问题，这是我用作解决scheme。

要使用此解决scheme，源表和目标表必须完全相同，并且在第一个表中必须具有唯一的id和自动增量（以便相同的id不会被重用）。

可以说table1和table2有这个结构

 |id|field1|field2 

你可以做这两个查询：

 INSERT INTO table2 SELECT * FROM table1 WHERE DELETE FROM table1 WHERE table1.id in (SELECT table2.id FROM table2) 

Answer 6

 BEGIN; INSERT INTO persons_table select * from customer_table where person_name = 'tom'; DELETE FROM customer_table where person_name = 'tom'; COMMIT;