MySql中两个时间戳的区别在几天？

我怎样才能获得两天时间戳之间的差异？ 我应该使用这个date时间列吗？

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我把我的专栏切换到date时间。 简单的减法似乎没有在几天内给我一个结果。

mysql> SELECT NOW(), last_confirmation_attempt, NOW() - last_confirmation_attempt AS diff FROM DateClubs HAVING diff IS NOT NULL ; +---------------------+---------------------------+-----------------+ | NOW() | last_confirmation_attempt | diff | +---------------------+---------------------------+-----------------+ | 2010-03-30 10:52:31 | 2010-03-16 10:41:47 | 14001084.000000 | +---------------------+---------------------------+-----------------+ 1 row in set (0.00 sec) 

我不认为diff是在几秒钟内，因为当我在一天（86,400）的秒数除diff ，我没有得到一个合理的答案：

 mysql> SELECT NOW(), last_confirmation_attempt, ( NOW() - last_confirmation_attempt) / 86400 AS diff FROM DateClubs HAVING diff IS NOT NULL ; +---------------------+---------------------------+----------------+ | NOW() | last_confirmation_attempt | diff | +---------------------+---------------------------+----------------+ | 2010-03-30 10:58:58 | 2010-03-16 10:41:47 | 162.0568402778 | +---------------------+---------------------------+----------------+ 1 row in set (0.00 sec) 

Answer 1

如果您很乐意忽略列中的时间部分， DATEDIFF（）会在几天内为您提供所需的差异。

 SELECT DATEDIFF('2010-10-08 18:23:13', '2010-09-21 21:40:36') AS days; +------+ | days | +------+ | 17 | +------+ 

Answer 2

我知道已经很老了，但是我只是为了说 – 我正在寻找同样的问题，到了这里，但是我需要几天的时间。

我使用了SELECT (UNIX_TIMESTAMP(DATE1) - UNIX_TIMESTAMP(DATE2))/60/60/24 Unix_timestamp以秒为单位返回差异，然后我分为几分钟（秒/ 60），几小时（分钟/ 60），几天/ 24）。

Answer 3

如果您想以完整的TIMESTAMP格式返回，请尝试下列操作： –

  SELECT TIMEDIFF(`call_end_time`, `call_start_time`) as diff from tablename; 

回报如

  diff - - - 00:05:15 

Answer 4

 CREATE TABLE t (d1 timestamp, d2 timestamp); INSERT INTO t VALUES ('2010-03-11 12:00:00', '2010-03-30 05:00:00'); INSERT INTO t VALUES ('2010-03-11 12:00:00', '2010-03-30 13:00:00'); INSERT INTO t VALUES ('2010-03-11 00:00:00', '2010-03-30 13:00:00'); INSERT INTO t VALUES ('2010-03-10 12:00:00', '2010-03-30 13:00:00'); INSERT INTO t VALUES ('2010-03-10 12:00:00', '2010-04-01 13:00:00'); SELECT d2, d1, DATEDIFF(d2, d1) AS diff FROM t; +---------------------+---------------------+------+ | d2 | d1 | diff | +---------------------+---------------------+------+ | 2010-03-30 05:00:00 | 2010-03-11 12:00:00 | 19 | | 2010-03-30 13:00:00 | 2010-03-11 12:00:00 | 19 | | 2010-03-30 13:00:00 | 2010-03-11 00:00:00 | 19 | | 2010-03-30 13:00:00 | 2010-03-10 12:00:00 | 20 | | 2010-04-01 13:00:00 | 2010-03-10 12:00:00 | 22 | +---------------------+---------------------+------+ 5 rows in set (0.00 sec) 

Answer 5

SELECT DATEDIFF( now(), '2013-06-20' );

这里过时了两个论点“最新”，“从最新”

我所做的是使用now（）函数，我不能。 自2013年6月20日至今天。

Answer 6

如果你需要天数的差异达到第二个：

SELECT TIMESTAMPDIFF（SECOND，'2010-09-21 21:40:36'，'2010-10-08 18:23:13'）/ 86400 AS diff

将返回16.8629天。