MySQL中允许嵌套事务吗？

MySQL是否允许使用嵌套事务？

Answer 1

InnoDB支持SAVEPOINTS 。

您可以执行以下操作：

 CREATE TABLE t_test (id INT NOT NULL PRIMARY KEY) ENGINE=InnoDB; START TRANSACTION; INSERT INTO t_test VALUES (1); SELECT * FROM t_test; id --- 1 SAVEPOINT tran2; INSERT INTO t_test VALUES (2); SELECT * FROM t_test; id --- 1 2 ROLLBACK TO tran2; SELECT * FROM t_test; id --- 1 ROLLBACK; SELECT * FROM t_test; id --- 

Answer 2

从MySQL文档：

事务不能嵌套。 当您发出START TRANSACTION语句或其同义词之一时，这是对任何当前事务执行的隐式提交的结果。 https://dev.mysql.com/doc/refman/5.7/en/implicit-commit.html

Answer 3

如果你使用php，那么你可以在https://github.com/Enelar/phpsql中感兴趣。它支持mysql和pgsql，并且可以扩展到其他连接器。;

 function TransferMoney() { // Nested transaction code could not even know that he nested $trans3 = db::Begin(); if (!db::Query("--Withdraw money from user", [$uid, $amount], true)) return $trans3->Rollback(); db::Query("--Deposit money to system"); return $trans3->Commit(); } $trans = db::Begin(); db::Query("--Give item to user inventory"); $trans2 = $trans->Begin(); $trans2->Query("--Try some actions and then decide to rollback"); $trans2->Rollback(); // Commit or rollback depending on money transfer result return $trans->Finish(TransferMoney());