如何切换到iPhone 5的不同Storyboard？

就像一个应用程序为iPad和iPhone使用不同的故事板一样，我希望我的应用程序为iPhone 5使用不同的故事板。由于Info.plist中没有select为iPhone 5select默认故事板的选项，我将如何以编程方式调用故事板？

我不想使用AutoLayout这个应用程序，除非它绝对是最后的手段。 我了解如何检测用户是否正在使用iPhone 5或具有相同屏幕尺寸的其他设备。 我只需要知道如何设置没有plist的默认情节串连图板。

Answer 1

我几周前正在寻找相同的答案这里是我的解决scheme希望帮助..

-(void)initializeStoryBoardBasedOnScreenSize { if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone) { // The iOS device = iPhone or iPod Touch CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size; if (iOSDeviceScreenSize.height == 480) { // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured) // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35 UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil]; // Instantiate the initial view controller object from the storyboard UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController]; // Instantiate a UIWindow object and initialize it with the screen size of the iOS device self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; // Set the initial view controller to be the root view controller of the window object self.window.rootViewController = initialViewController; // Set the window object to be the key window and show it [self.window makeKeyAndVisible]; } if (iOSDeviceScreenSize.height == 568) { // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured) // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4 UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil]; // Instantiate the initial view controller object from the storyboard UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController]; // Instantiate a UIWindow object and initialize it with the screen size of the iOS device self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; // Set the initial view controller to be the root view controller of the window object self.window.rootViewController = initialViewController; // Set the window object to be the key window and show it [self.window makeKeyAndVisible]; } } else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) { // The iOS device = iPad UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController; UINavigationController *navigationController = [splitViewController.viewControllers lastObject]; splitViewController.delegate = (id)navigationController.topViewController; } } 

在AppDelegate下调用这个方法ddiFinishLaunchingWithOptions：方法也不要忘记你的故事板的名字正确

希望有帮助…

Answer 2

这工作对我来说 – 略微改进与包装获取故事板function

 -(UIStoryboard*) getStoryboard { UIStoryboard *storyBoard = nil; if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) { storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil]; }else{ if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone){ // The iOS device = iPhone or iPod Touch CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size; if (iOSDeviceScreenSize.height == 480){ // iPhone 3/4x storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_4" bundle:nil]; }else if (iOSDeviceScreenSize.height == 568){ // iPhone 5 etc storyBoard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone_5" bundle:nil]; } } } ASSERT(storyBoard); return storyBoard; } UIStoryboard* mainStoryBoard = [self getStoryboard]; self.initialViewController = [mainStoryBoard instantiateInitialViewController]; self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; self.window.rootViewController = self.initialViewController; [self.window makeKeyAndVisible];