我怎样才能将一个date时间对象转换为Python时代（unix时间）以来的毫秒数？

我有一个Python的datetime对象，我想转换为UNIX时间，或自1970年以来的秒/毫秒。

我如何做到这一点？

Answer 1

在我看来，做到这一点的最简单的方法是

 import datetime epoch = datetime.datetime.utcfromtimestamp(0) def unix_time_millis(dt): return (dt - epoch).total_seconds() * 1000.0 

Answer 2

 >>> import datetime >>> # replace datetime.datetime.now() with your datetime object >>> int(datetime.datetime.now().strftime("%s")) * 1000 1312908481000 

或者时间模块的帮助（没有date格式）：

 >>> import datetime, time >>> # replace datetime.datetime.now() with your datetime object >>> time.mktime(datetime.datetime.now().timetuple()) * 1000 1312908681000.0 

通过http://pleac.sourceforge.net/pleac_python/datesandtimes.html帮助解答;

文档：

• time.mktime
• datetime.timetuple

Answer 3

在Python 3.3中，添加新的方法。

 datetime.timestamp() 

https://docs.python.org/3.3/library/datetime.html#datetime.datetime.timestamp

Answer 4

您可以使用Delorean在空间和时间旅行！

 import datetime import delorean dt = datetime.datetime.utcnow() delorean.Delorean(dt, timezone="UTC").epoch 

http://delorean.readthedocs.org/en/latest/quickstart.html

Answer 5

这是我如何做到的：

 from datetime import datetime from time import mktime dt = datetime.now() sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0 millis_since_epoch = sec_since_epoch * 1000 

Answer 6

从python文档推荐的方式

Answer 7

 >>> import datetime >>> import time >>> import calendar >>> #your datetime object >>> now = datetime.datetime.now() >>> now datetime.datetime(2013, 3, 19, 13, 0, 9, 351812) >>> #use datetime module's timetuple method to get a `time.struct_time` object.[1] >>> tt = datetime.datetime.timetuple(now) >>> tt time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9, tm_wday=1, tm_yday=78, tm_isdst=-1) >>> #If your datetime object is in utc you do this way. [2](see the first table on docs) >>> sec_epoch_utc = calendar.timegm(tt) * 1000 >>> sec_epoch_utc 1363698009 >>> #If your datetime object is in local timeformat you do this way >>> sec_epoch_loc = time.mktime(tt) * 1000 >>> sec_epoch_loc 1363678209.0 

[1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple

[2] http://docs.python.org/2/library/time.html

Answer 8

 from datetime import datetime from calendar import timegm # Note: if you pass in a naive dttm object it's assumed to already be in UTC def unix_time(dttm=None): if dttm is None: dttm = datetime.utcnow() return timegm(dttm.utctimetuple()) print "Unix time now: %d" % unix_time() print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0)) 

Answer 9

 import time seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000 

Answer 10

这是另一种解决时间对象正常化的解决scheme：

 def to_unix_time(timestamp): epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object delta = my_time - epoch return delta.total_seconds() * 1000.0 

Answer 11

这个隐蔽的date时间到unixtimestampmillis的其他解决scheme。

 private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc); public static long GetCurrentUnixTimestampMillis() { DateTime localDateTime, univDateTime; localDateTime = DateTime.Now; univDateTime = localDateTime.ToUniversalTime(); return (long)(univDateTime - UnixEpoch).TotalMilliseconds; }