如何在C＃中生成UUID
我正在编程创build一个.idl文件。 如何以编程方式为接口和方法创buildUUID。
我可以编程生成UUID吗？
您可能正在寻找System.Guid.NewGuid() 。
注意：.NET Guid和（RFC4122）UUID的string表示forms是相同的， 而存储格式则不相同。 .NET的前三个Guid部分以little-endian字节进行交易。
如果您要传输字节（例如，以base64为单位），则不能只使用Guid.ToByteArray()并对其进行编码。 你需要Array.Reverse前三部分（Data1-3）。
我这样做：
var rfc4122bytes = Convert.FromBase64String("aguidthatIgotonthewire=="); Array.Reverse(rfc4122bytes,0,4); Array.Reverse(rfc4122bytes,4,2); Array.Reverse(rfc4122bytes,6,2); var guid = new Guid(rfc4122bytes);
看到这个答案为特定的.NET实现细节。
编辑 ：感谢代码游侠杰夫·沃克指出，内部与进出字节数组构造函数和ToByteArray()的字节数组的格式不相关。
这里是客户端“顺序guid”解决scheme。
http://www.pinvoke.net/default.aspx/rpcrt4.uuidcreate
using System; using System.Runtime.InteropServices; namespace MyCompany.MyTechnology.Framework.CrossDomain.GuidExtend { public static class Guid { /* Original Reference for Code: http://www.pinvoke.net/default.aspx/rpcrt4/UuidCreateSequential.html */ [DllImport("rpcrt4.dll", SetLastError = true)] static extern int UuidCreateSequential(out System.Guid guid); public static System.Guid NewGuid() { return CreateSequentialUuid(); } public static System.Guid CreateSequentialUuid() { const int RPC_S_OK = 0; System.Guid g; int hr = UuidCreateSequential(out g); if (hr != RPC_S_OK) throw new ApplicationException("UuidCreateSequential failed: " + hr); return g; } /* Text From URL above: UuidCreateSequential (rpcrt4) Type a page name and press Enter. You'll jump to the page if it exists, or you can create it if it doesn't. To create a page in a module other than rpcrt4, prefix the name with the module name and a period. . Summary Creates a new UUID C# Signature: [DllImport("rpcrt4.dll", SetLastError=true)] static extern int UuidCreateSequential(out Guid guid); VB Signature: Declare Function UuidCreateSequential Lib "rpcrt4.dll" (ByRef id As Guid) As Integer User-Defined Types: None. Notes: Microsoft changed the UuidCreate function so it no longer uses the machine's MAC address as part of the UUID. Since CoCreateGuid calls UuidCreate to get its GUID, its output also changed. If you still like the GUIDs to be generated in sequential order (helpful for keeping a related group of GUIDs together in the system registry), you can use the UuidCreateSequential function. CoCreateGuid generates random-looking GUIDs like these: 92E60A8A-2A99-4F53-9A71-AC69BD7E4D75 BB88FD63-DAC2-4B15-8ADF-1D502E64B92F 28F8800C-C804-4F0F-B6F1-24BFC4D4EE80 EBD133A6-6CF3-4ADA-B723-A8177B70D268 B10A35C0-F012-4EC1-9D24-3CC91D2B7122 UuidCreateSequential generates sequential GUIDs like these: 19F287B4-8830-11D9-8BFC-000CF1ADC5B7 19F287B5-8830-11D9-8BFC-000CF1ADC5B7 19F287B6-8830-11D9-8BFC-000CF1ADC5B7 19F287B7-8830-11D9-8BFC-000CF1ADC5B7 19F287B8-8830-11D9-8BFC-000CF1ADC5B7 Here is a summary of the differences in the output of UuidCreateSequential: The last six bytes reveal your MAC address Several GUIDs generated in a row are sequential Tips & Tricks: Please add some! Sample Code in C#: static Guid UuidCreateSequential() { const int RPC_S_OK = 0; Guid g; int hr = UuidCreateSequential(out g); if (hr != RPC_S_OK) throw new ApplicationException ("UuidCreateSequential failed: " + hr); return g; } Sample Code in VB: Sub Main() Dim myId As Guid Dim code As Integer code = UuidCreateSequential(myId) If code <> 0 Then Console.WriteLine("UuidCreateSequential failed: {0}", code) Else Console.WriteLine(myId) End If End Sub */ } }
关键字：CreateSequentialUUID SequentialUUID
我不知道方法; 但是，可以通过以下方式将GUIDtypes完成：
Guid iid = System.Runtime.InteropServices.Marshal.GenerateGuidForType(typeof(IFoo));
我有一个GitHub Gist与Java中的UUID实现在C＃中： https ： //gist.github.com/rickbeerendonk/13655dd24ec574954366
UUID可以从最小和最重要的位创build，就像在Java中一样。 它也暴露了他们。 该实现具有显式转换为GUID和GUID的隐式转换。
