在C＃中将数据表转换为JSON

1. 我想从数据库中获取logging到一个DataTable 。
2. 然后将DataTable转换成JSON对象。
3. 将JSON对象返回给我的JavaScript函数。

我使用这个代码通过调用：

 string result = JsonConvert.SerializeObject(DatatableToDictionary(queryResult, "Title"), Newtonsoft.Json.Formatting.Indented); 

要将DataTable转换为JSON，它可以正常工作并返回以下内容：

 { "1": { "viewCount": 703, "clickCount": 98 }, "2": { "viewCount": 509, "clickCount": 85 }, "3": { "viewCount": 578, "clickCount": 86 }, "4": { "viewCount": 737, "clickCount": 108 }, "5": { "viewCount": 769, "clickCount": 130 } } 

但我希望它返回以下内容：

 {"records":[ { "Title": 1, "viewCount": 703, "clickCount": 98 }, { "Title": 2, "viewCount": 509, "clickCount": 85 }, { "Title": 3, "viewCount": 578, "clickCount": 86 }, { "Title": 4, "viewCount": 737, "clickCount": 108 }, { "Title": 5, "viewCount": 769, "clickCount": 130 } ]} 

我该怎么做？

Answer 1

C＃，VB.NET中的转换数据表到JSONstring的代码片段可能会帮助你。 它使用System.Web.Script.Serialization.JavaScriptSerializer将内容序列化为JSON格式：

 public string ConvertDataTabletoString() { DataTable dt = new DataTable(); using (SqlConnection con = new SqlConnection("Data Source=SureshDasari;Initial Catalog=master;Integrated Security=true")) { using (SqlCommand cmd = new SqlCommand("select title=City,lat=latitude,lng=longitude,description from LocationDetails", con)) { con.Open(); SqlDataAdapter da = new SqlDataAdapter(cmd); da.Fill(dt); System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer(); List<Dictionary<string, object>> rows = new List<Dictionary<string, object>>(); Dictionary<string, object> row; foreach (DataRow dr in dt.Rows) { row = new Dictionary<string, object>(); foreach (DataColumn col in dt.Columns) { row.Add(col.ColumnName, dr[col]); } rows.Add(row); } return serializer.Serialize(rows); } } } 

Answer 2

我们可以用两个简单的方法来完成任务，一个是使用Json.NET dll，另一个是使用StringBuilder类。

使用Newtonsoft Json.NET

  string JSONresult; JSONresult = JsonConvert.SerializeObject(dt); Response.Write(JSONresult); 

参考链接 ： – Newtonsoft：在ASP.Net中将DataTable转换为JSON对象C＃

使用StringBuilder

 public string DataTableToJsonObj(DataTable dt) { DataSet ds = new DataSet(); ds.Merge(dt); StringBuilder JsonString = new StringBuilder(); if (ds != null && ds.Tables[0].Rows.Count > 0) { JsonString.Append("["); for (int i = 0; i < ds.Tables[0].Rows.Count; i++) { JsonString.Append("{"); for (int j = 0; j < ds.Tables[0].Columns.Count; j++) { if (j < ds.Tables[0].Columns.Count - 1) { JsonString.Append("\"" + ds.Tables[0].Columns[j].ColumnName.ToString() + "\":" + "\"" + ds.Tables[0].Rows[i][j].ToString() + "\","); } else if (j == ds.Tables[0].Columns.Count - 1) { JsonString.Append("\"" + ds.Tables[0].Columns[j].ColumnName.ToString() + "\":" + "\"" + ds.Tables[0].Rows[i][j].ToString() + "\""); } } if (i == ds.Tables[0].Rows.Count - 1) { JsonString.Append("}"); } else { JsonString.Append("},"); } } JsonString.Append("]"); return JsonString.ToString(); } else { return null; } } 

Answer 3

这与接受的答案有类似的方法，但使用LINQ将数据表转换为单行代码列表。

 //convert datatable to list using LINQ. Input datatable is "dt", returning list of "name:value" tuples var lst = dt.AsEnumerable() .Select(r => r.Table.Columns.Cast<DataColumn>() .Select(c => new KeyValuePair<string, object>(c.ColumnName, r[c.Ordinal]) ).ToDictionary(z=>z.Key,z=>z.Value) ).ToList(); //now serialize it var serializer = new System.Web.Script.Serialization.JavaScriptSerializer(); return serializer.Serialize(lst); 

这是枚举数据表的一个非常有用的方法，通常需要大量的编码！ 这里有一些变化：

 //convert to list with array of values for each row var list1 = dt.AsEnumerable().Select(r => r.ItemArray.ToList()).ToList(); //convert to list of first column values only var list2 = dt.AsEnumerable().Select(r => r.ItemArray[0]).ToList(); // parse a datatable with conditions and get CSV string string MalesOver21 = string.Join(",", dt.AsEnumerable() .Where(r => r["GENDER"].ToString()=="M" && r.Field<int>("AGE")>21) .Select(r => r.Field<string>("FULLNAME")) ); 

Answer 4

没有使用JavaScript序列化的替代方法：

  public static string DataTableToJSON(DataTable Dt) { string[] StrDc = new string[Dt.Columns.Count]; string HeadStr = string.Empty; for (int i = 0; i < Dt.Columns.Count; i++) { StrDc[i] = Dt.Columns[i].Caption; HeadStr += "\"" + StrDc[i] + "\":\"" + StrDc[i] + i.ToString() + "¾" + "\","; } HeadStr = HeadStr.Substring(0, HeadStr.Length - 1); StringBuilder Sb = new StringBuilder(); Sb.Append("["); for (int i = 0; i < Dt.Rows.Count; i++) { string TempStr = HeadStr; for (int j = 0; j < Dt.Columns.Count; j++) { TempStr = TempStr.Replace(Dt.Columns[j] + j.ToString() + "¾", Dt.Rows[i][j].ToString().Trim()); } //Sb.AppendFormat("{{{0}}},",TempStr); Sb.Append("{"+TempStr + "},"); } Sb = new StringBuilder(Sb.ToString().Substring(0, Sb.ToString().Length - 1)); if(Sb.ToString().Length>0) Sb.Append("]"); return StripControlChars(Sb.ToString()); } //To strip control characters: //A character that does not represent a printable character but //serves to initiate a particular action. public static string StripControlChars(string s) { return Regex.Replace(s, @"[^\x20-\x7F]", ""); } 

Answer 5

你可以使用Alireza Maddah指定的相同方法，如果你想使用两个数据表到一个json数组中，可以采用以下方法：

 public string ConvertDataTabletoString() { DataTable dt = new DataTable(); DataTable dt1 = new DataTable(); using (SqlConnection con = new SqlConnection("Data Source=SureshDasari;Initial Catalog=master;Integrated Security=true")) { using (SqlCommand cmd = new SqlCommand("select title=City,lat=latitude,lng=longitude,description from LocationDetails", con)) { con.Open(); SqlDataAdapter da = new SqlDataAdapter(cmd); da.Fill(dt); System.Web.Script.Serialization.JavaScriptSerializer serializer = new System.Web.Script.Serialization.JavaScriptSerializer(); List<Dictionary<string, object>> rows = new List<Dictionary<string, object>>(); Dictionary<string, object> row; foreach (DataRow dr in dt.Rows) { row = new Dictionary<string, object>(); foreach (DataColumn col in dt.Columns) { row.Add(col.ColumnName, dr[col]); } rows.Add(row); } SqlCommand cmd1 = new SqlCommand("_another_query_", con); SqlDataAdapter da1 = new SqlDataAdapter(cmd1); da1.Fill(dt1); System.Web.Script.Serialization.JavaScriptSerializer serializer1 = new System.Web.Script.Serialization.JavaScriptSerializer(); Dictionary<string, object> row1; foreach (DataRow dr in dt1.Rows) //use the old variable rows only { row1 = new Dictionary<string, object>(); foreach (DataColumn col in dt1.Columns) { row1.Add(col.ColumnName, dr[col]); } rows.Add(row1); // Finally You can add into old json array in this way } return serializer.Serialize(rows); } } } 

您可以使用与数据表一样多的相同方式。

Answer 6

使用C＃.net将数据表转换为JSON

  public static object DataTableToJSON(DataTable table) { var list = new List<Dictionary<string, object>>(); foreach (DataRow row in table.Rows) { var dict = new Dictionary<string, object>(); foreach (DataColumn col in table.Columns) { dict[col.ColumnName] = (Convert.ToString(row[col])); } list.Add(dict); } JavaScriptSerializer serializer = new JavaScriptSerializer(); return serializer.Serialize(list); } 

Answer 7

要在Json方法中访问convert数据表值，请按照以下步骤操作：

 $.ajax({ type: "POST", url: "/Services.asmx/YourMethodName", data: "{}", contentType: "application/json; charset=utf-8", dataType: "json", success: function (data) { var parsed = $.parseJSON(data.d); $.each(parsed, function (i, jsondata) { $("#dividtodisplay").append("Title: " + jsondata.title + "<br/>" + "Latitude: " + jsondata.lat); }); }, error: function (XHR, errStatus, errorThrown) { var err = JSON.parse(XHR.responseText); errorMessage = err.Message; alert(errorMessage); } }); 

Answer 8

试试这个自定义函数。

  public static string DataTableToJsonObj(DataTable dt) { DataSet ds = new DataSet(); ds.Merge(dt); StringBuilder jsonString = new StringBuilder(); if (ds.Tables[0].Rows.Count > 0) { jsonString.Append("["); for (int rows = 0; rows < ds.Tables[0].Rows.Count; rows++) { jsonString.Append("{"); for (int cols = 0; cols < ds.Tables[0].Columns.Count; cols++) { jsonString.Append(@"""" + ds.Tables[0].Columns[cols].ColumnName + @""":"); /* //IF NOT LAST PROPERTY if (cols < ds.Tables[0].Columns.Count - 1) { GenerateJsonProperty(ds, rows, cols, jsonString); } //IF LAST PROPERTY else if (cols == ds.Tables[0].Columns.Count - 1) { GenerateJsonProperty(ds, rows, cols, jsonString, true); } */ var b = (cols < ds.Tables[0].Columns.Count - 1) ? GenerateJsonProperty(ds, rows, cols, jsonString) : (cols != ds.Tables[0].Columns.Count - 1) || GenerateJsonProperty(ds, rows, cols, jsonString, true); } jsonString.Append(rows == ds.Tables[0].Rows.Count - 1 ? "}" : "},"); } jsonString.Append("]"); return jsonString.ToString(); } return null; } private static bool GenerateJsonProperty(DataSet ds, int rows, int cols, StringBuilder jsonString, bool isLast = false) { // IF LAST PROPERTY THEN REMOVE 'COMMA' IF NOT LAST PROPERTY THEN ADD 'COMMA' string addComma = isLast ? "" : ","; if (ds.Tables[0].Rows[rows][cols] == DBNull.Value) { jsonString.Append(" null " + addComma); } else if (ds.Tables[0].Columns[cols].DataType == typeof(DateTime)) { jsonString.Append(@"""" + (((DateTime)ds.Tables[0].Rows[rows][cols]).ToString("yyyy-MM-dd HH':'mm':'ss")) + @"""" + addComma); } else if (ds.Tables[0].Columns[cols].DataType == typeof(string)) { jsonString.Append(@"""" + (ds.Tables[0].Rows[rows][cols]) + @"""" + addComma); } else if (ds.Tables[0].Columns[cols].DataType == typeof(bool)) { jsonString.Append(Convert.ToBoolean(ds.Tables[0].Rows[rows][cols]) ? "true" : "fasle"); } else { jsonString.Append(ds.Tables[0].Rows[rows][cols] + addComma); } return true; } 

Answer 9

 public static string ConvertIntoJson(DataTable dt) { var jsonString = new StringBuilder(); if (dt.Rows.Count > 0) { jsonString.Append("["); for (int i = 0; i < dt.Rows.Count; i++) { jsonString.Append("{"); for (int j = 0; j < dt.Columns.Count; j++) jsonString.Append("\"" + dt.Columns[j].ColumnName + "\":\"" + dt.Rows[i][j].ToString().Replace('"','\"') + (j < dt.Columns.Count - 1 ? "\"," : "\"")); jsonString.Append(i < dt.Rows.Count - 1 ? "}," : "}"); } return jsonString.Append("]").ToString(); } else { return "[]"; } } public static string ConvertIntoJson(DataSet ds) { var jsonString = new StringBuilder(); jsonString.Append("{"); for (int i = 0; i < ds.Tables.Count; i++) { jsonString.Append("\"" + ds.Tables[i].TableName + "\":"); jsonString.Append(ConvertIntoJson(ds.Tables[i])); if (i < ds.Tables.Count - 1) jsonString.Append(","); } jsonString.Append("}"); return jsonString.ToString(); } 

Answer 10

 //Common DLL client, server public class transferDataTable { public class myError { public string Message { get; set; } public int Code { get; set; } } public myError Error { get; set; } public List<string> ColumnNames { get; set; } public List<string> DataTypes { get; set; } public List<Object> Data { get; set; } public int Count { get; set; } } public static class ExtensionMethod { public static transferDataTable LoadData(this transferDataTable transfer, DataTable dt) { if (dt != null) { transfer.DataTypes = new List<string>(); transfer.ColumnNames = new List<string>(); foreach (DataColumn c in dt.Columns) { transfer.ColumnNames.Add(c.ColumnName); transfer.DataTypes.Add(c.DataType.ToString()); } transfer.Data = new List<object>(); foreach (DataRow dr in dt.Rows) { foreach (DataColumn col in dt.Columns) { transfer.Data.Add(dr[col] == DBNull.Value ? null : dr[col]); } } transfer.Count = dt.Rows.Count; } return transfer; } public static DataTable GetDataTable(this transferDataTable transfer, bool ConvertToLocalTime = true) { if (transfer.Error != null || transfer.ColumnNames == null || transfer.DataTypes == null || transfer.Data == null) return null; int columnsCount = transfer.ColumnNames.Count; DataTable dt = new DataTable(); for (int i = 0; i < columnsCount; i++ ) { Type colType = Type.GetType(transfer.DataTypes[i]); dt.Columns.Add(new DataColumn(transfer.ColumnNames[i], colType)); } int index = 0; DataRow row = dt.NewRow(); foreach (object o in transfer.Data) { if (ConvertToLocalTime && o != null && o.GetType() == typeof(DateTime)) { DateTime dat = Convert.ToDateTime(o); row[index] = dat.ToLocalTime(); } else row[index] = o == null ? DBNull.Value : o; index++; if (columnsCount == index) { index = 0; dt.Rows.Add(row); row = dt.NewRow(); } } return dt; } } //Server [OperationContract] [WebInvoke(Method = "GET", ResponseFormat = WebMessageFormat.Json, BodyStyle = WebMessageBodyStyle.WrappedRequest, UriTemplate = "json/data")] transferDataTable _Data(); public transferDataTable _Data() { try { using (SqlConnection con = new SqlConnection(ConfigurationManager.AppSettings["myConnString"])) { con.Open(); DataSet ds = new DataSet(); SqlDataAdapter myAdapter = new SqlDataAdapter("SELECT * FROM tbGalleries", con); myAdapter.Fill(ds, "table"); DataTable dt = ds.Tables["table"]; return new transferDataTable().LoadData(dt); } } catch(Exception ex) { return new transferDataTable() { Error = new transferDataTable.myError() { Message = ex.Message, Code = ex.HResult } }; } } //Client Response = Vossa.getAPI(serviceUrl + "json/data"); transferDataTable transfer = new JavaScriptSerializer().Deserialize<transferDataTable>(Response); if (transfer.Error == null) { DataTable dt = transfer.GetDataTable(); dbGrid.ItemsSource = dt.DefaultView; } else MessageBox.Show(transfer.Error.Message, "Error", MessageBoxButton.OK, MessageBoxImage.Error); 

Answer 11

我有简单的function转换datatable jsonstring。

我用Newtonsoft来生成string。 我不使用Newtonsoft来完全序列化Datatable。 小心这个。

也许这可能是有用的。

  private string DataTableToJson(DataTable dt) { if (dt == null) { return "[]"; }; if (dt.Rows.Count < 1) { return "[]"; }; JArray array = new JArray(); foreach(DataRow dr in dt.Rows) { JObject item = new JObject(); foreach(DataColumn col in dt.Columns) { item.Add(col.ColumnName, dr[col.ColumnName] ? .ToString()); } array.Add(item); } return array.ToString(Newtonsoft.Json.Formatting.Indented); }