如何从android调用.NET Web服务？

我需要调用一个类似于"http://192.168.1.19/TestWeb/WebService.asmx"的URL的Web服务。

请任何人帮助我一个完整的例子？

Answer 1

最后，我为自己的问题得到了解决scheme。

这里是代码：

 package projects.ksoap2sample; import org.ksoap2.SoapEnvelope; import org.ksoap2.serialization.SoapObject; import org.ksoap2.serialization.SoapSerializationEnvelope; import org.ksoap2.transport.HttpTransportSE; import android.app.*; import android.os.*; import android.widget.TextView; public class ksoap2sample extends Activity { /** Called when the activity is first created. */ private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld"; private static final String METHOD_NAME = "HelloWorld"; private static final String NAMESPACE = "http://tempuri.org/"; private static final String URL = "http://192.168.1.19/TestWeb/WebService.asmx"; TextView tv; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); tv=(TextView)findViewById(R.id.text1); call(); } public void call() { try { SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); request.addProperty("passonString", "Rajapandian"); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet=true; envelope.setOutputSoapObject(request); HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); androidHttpTransport.call(SOAP_ACTION, envelope); Object result = (Object)envelope.getResponse(); tv.setText(result.toString()); } catch (Exception e) { tv.setText(e.getMessage()); } } } 

问候Rajapandian