以编程方式获取网关和子网掩码的详细信息
如何在Android中获取网关和子网掩码的详细信息？
我在android.net包中find了一个名为DhcpInfo的类。 它有一些公共variables存储当前networking参数的值。 但问题是他们返回从8Bit移位二进制转换的整数值。
示例图像描述你的情景：
****这是一个示例代码：**
** java文件：****
package com.schogini.dhcp; import android.app.Activity; import android.content.Context; import android.os.Bundle; import android.widget.TextView; import android.net.*; import android.net.wifi.WifiManager; public class dhcpInfo extends Activity { public String s_dns1 ; public String s_dns2; public String s_gateway; public String s_ipAddress; public String s_leaseDuration; public String s_netmask; public String s_serverAddress; TextView info; DhcpInfo d; WifiManager wifii; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); wifii= (WifiManager) getSystemService(Context.WIFI_SERVICE); d=wifii.getDhcpInfo(); s_dns1="DNS 1: "+String.valueOf(d.dns1); s_dns2="DNS 2: "+String.valueOf(d.dns2); s_gateway="Default Gateway: "+String.valueOf(d.gateway); s_ipAddress="IP Address: "+String.valueOf(d.ipAddress); s_leaseDuration="Lease Time: "+String.valueOf(d.leaseDuration); s_netmask="Subnet Mask: "+String.valueOf(d.netmask); s_serverAddress="Server IP: "+String.valueOf(d.serverAddress); //dispaly them info= (TextView) findViewById(R.id.infolbl); info.setText("Network Info\n"+s_dns1+"\n"+s_dns2+"\n"+s_gateway+"\n"+s_ipAddress+"\n"+s_leaseDuration+"\n"+s_netmask+"\n"+s_serverAddress); } }
xml编码：
<?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.schogini.dhcp" android:versionCode="1" android:versionName="1.0"> <uses-sdk android:minSdkVersion="4" /> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name=".dhcpInfo" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> <uses-permission android:name="android.permission.ACCESS_WIFI_STATE" /> </manifest>
我试图将整数值转换为其等价物，但我不能。 如果你这样做，你可以回发..再见..
更新：一些如何设法将IP转换为v4格式从整数forms转换为IPv4格式：
public String intToIp(int i) { return ((i >> 24 ) & 0xFF ) + "." + ((i >> 16 ) & 0xFF) + "." + ((i >> 8 ) & 0xFF) + "." + ( i & 0xFF) ; }
IMAGE Courtesy： http : //www.bennadel.com/blog/1830-Converting-IP-Addresses-To-And-From-Integer-Values-With-ColdFusion.htm
Formatter.formatIpAddress（int）已被弃用，我们不想使用已弃用的方法吗？
AndroidKid的这个版本是以某种方式颠倒了，但是这应该解决它：
public String intToIp(int addr) { return ((addr & 0xFF) + "." + ((addr >>>= 8) & 0xFF) + "." + ((addr >>>= 8) & 0xFF) + "." + ((addr >>>= 8) & 0xFF)); }
资料来源： http : //www.devdaily.com/java/jwarehouse/android/core/java/android/net/DhcpInfo.java.shtml
要格式化ip，请尝试使用：
import android.text.format.Formatter; public String FormatIP(int IpAddress) { return Formatter.formatIpAddress(IpAddress); }
使用Formatter.formatIpAddress(mask); 掩码是你的int。
String maskk = Formatter.formatIpAddress(mask);
而不是得到255.255.255.0，只需要改变顺序;）所以你将能够得到正确的顺序…
public String intToIp(int i) { return (i & 0xFF) + "." + ((i >> 8 ) & 0xFF) + "." + ((i >> 16 ) & 0xFF) + "." + ((i >> 24 ) & 0xFF) ; }
这是一个旧的线程，但我发现了android API（包android.net.NetworkUtils ）使用的官方function：
/** * Convert a IPv4 address from an integer to an InetAddress. * @param hostAddress an int corresponding to the IPv4 address in network byte order */ public static InetAddress intToInetAddress(int hostAddress) { byte[] addressBytes = { (byte)(0xff & hostAddress), (byte)(0xff & (hostAddress >> 8)), (byte)(0xff & (hostAddress >> 16)), (byte)(0xff & (hostAddress >> 24)) }; try { return InetAddress.getByAddress(addressBytes); } catch (UnknownHostException e) { throw new AssertionError(); } }
一旦你有了InetAddress你可以通过这种方式获得格式化的string：
intToInetAddress(d.gateway).getHostAddress()
虽然古老，像魅力的作品。
tvGateway.setText（Formatter.formatIpAddress（dhcpInfo.gateway））;
