外键和它们引用的表的列表

我试图find一个查询，将返回一个表的外键列表和他们引用的表和列。 我在那里的一半

SELECT a.table_name, a.column_name, a.constraint_name, c.owner FROM ALL_CONS_COLUMNS A, ALL_CONSTRAINTS C where A.CONSTRAINT_NAME = C.CONSTRAINT_NAME and a.table_name=:TableName and C.CONSTRAINT_TYPE = 'R' 

但是我仍然需要知道哪个表和主键被这个键引用。 我怎么得到这个？

Answer 1

引用的主键在表r_owner的列r_owner和r_constraint_name进行了ALL_CONSTRAINTS 。 这会给你你想要的信息：

 SELECT a.table_name, a.column_name, a.constraint_name, c.owner, -- referenced pk c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name JOIN all_constraints c_pk ON c.r_owner = c_pk.owner AND c.r_constraint_name = c_pk.constraint_name WHERE c.constraint_type = 'R' AND a.table_name = :TableName 

Answer 2

这是一个我们使用的通用脚本，非常方便。

保存它，所以你可以直接执行（@ fkeys.sql）。 它会让你按照所有者和Parent或Child表进行search，并显示外键关系。 当前的脚本显式地后台到C：\ SQLRPTS，所以你需要创build一个你想要使用的东西。

 REM ######################################################################## REM ## REM ## fkeys.sql REM ## REM ## Displays the foreign key relationships REM ## REM ####################################################################### CLEAR BREAK CLEAR COL SET LINES 200 SET PAGES 54 SET NEWPAGE 0 SET WRAP OFF SET VERIFY OFF SET FEEDBACK OFF break on table_name skip 2 on constraint_name on r_table_name skip 1 column CHILDCOL format a60 head 'CHILD COLUMN' column PARENTCOL format a60 head 'PARENT COLUMN' column constraint_name format a30 head 'FK CONSTRAINT NAME' column delete_rule format a15 column bt noprint column bo noprint TTITLE LEFT _DATE CENTER 'FOREIGN KEY RELATIONSHIPS ON &new_prompt' RIGHT 'PAGE:'FORMAT 999 SQL.PNO SKIP 2 SPOOL C:\SQLRPTS\FKeys_&new_prompt ACCEPT OWNER_NAME PROMPT 'Enter Table Owner (or blank for all): ' ACCEPT PARENT_TABLE_NAME PROMPT 'Enter Parent Table or leave blank for all: ' ACCEPT CHILD_TABLE_NAME PROMPT 'Enter Child Table or leave blank for all: ' select b.owner || '.' || b.table_name || '.' || b.column_name CHILDCOL, b.position, c.owner || '.' || c.table_name || '.' || c.column_name PARENTCOL, a.constraint_name, a.delete_rule, b.table_name bt, b.owner bo from all_cons_columns b, all_cons_columns c, all_constraints a where b.constraint_name = a.constraint_name and a.owner = b.owner and b.position = c.position and c.constraint_name = a.r_constraint_name and c.owner = a.r_owner and a.constraint_type = 'R' and c.owner like case when upper('&OWNER_NAME') is null then '%' else upper('&OWNER_NAME') end and c.table_name like case when upper('&PARENT_TABLE_NAME') is null then '%' else upper('&PARENT_TABLE_NAME') end and b.table_name like case when upper('&CHILD_TABLE_NAME') is null then '%' else upper('&CHILD_TABLE_NAME') end order by 7,6,4,2 / SPOOL OFF TTITLE OFF SET FEEDBACK ON SET VERIFY ON CLEAR BREAK CLEAR COL SET PAGES 24 SET LINES 100 SET NEWPAGE 1 UNDEF OWNER 

Answer 3

尝试这个：

 select * from all_constraints where r_constraint_name in (select constraint_name from all_constraints where table_name='YOUR_TABLE_NAME'); 

Answer 4

这将遍历给定表和列的外键层次结构，并返回来自子孙，以及所有后代表的列。 它使用子查询将r_table_name和r_column_name添加到user_constraints，然后使用它们连接行。

 select distinct table_name, constraint_name, column_name, r_table_name, position, constraint_type from ( SELECT uc.table_name, uc.constraint_name, cols.column_name, (select table_name from user_constraints where constraint_name = uc.r_constraint_name) r_table_name, (select column_name from user_cons_columns where constraint_name = uc.r_constraint_name and position = cols.position) r_column_name, cols.position, uc.constraint_type FROM user_constraints uc inner join user_cons_columns cols on uc.constraint_name = cols.constraint_name where constraint_type != 'C' ) start with table_name = 'MY_TABLE_NAME' and column_name = 'MY_COLUMN_NAME' connect by nocycle prior table_name = r_table_name and prior column_name = r_column_name; 

Answer 5

这是另一个解决scheme。 使用sys的默认视图非常慢（在我的情况下大约10s）。 这比这个要快得多（约0.5秒）。

 SELECT CONST.NAME AS CONSTRAINT_NAME, RCONST.NAME AS REF_CONSTRAINT_NAME, OBJ.NAME AS TABLE_NAME, COALESCE(ACOL.NAME, COL.NAME) AS COLUMN_NAME, CCOL.POS# AS POSITION, ROBJ.NAME AS REF_TABLE_NAME, COALESCE(RACOL.NAME, RCOL.NAME) AS REF_COLUMN_NAME, RCCOL.POS# AS REF_POSITION FROM SYS.CON$ CONST INNER JOIN SYS.CDEF$ CDEF ON CDEF.CON# = CONST.CON# INNER JOIN SYS.CCOL$ CCOL ON CCOL.CON# = CONST.CON# INNER JOIN SYS.COL$ COL ON (CCOL.OBJ# = COL.OBJ#) AND (CCOL.INTCOL# = COL.INTCOL#) INNER JOIN SYS.OBJ$ OBJ ON CCOL.OBJ# = OBJ.OBJ# LEFT JOIN SYS.ATTRCOL$ ACOL ON (CCOL.OBJ# = ACOL.OBJ#) AND (CCOL.INTCOL# = ACOL.INTCOL#) INNER JOIN SYS.CON$ RCONST ON RCONST.CON# = CDEF.RCON# INNER JOIN SYS.CCOL$ RCCOL ON RCCOL.CON# = RCONST.CON# INNER JOIN SYS.COL$ RCOL ON (RCCOL.OBJ# = RCOL.OBJ#) AND (RCCOL.INTCOL# = RCOL.INTCOL#) INNER JOIN SYS.OBJ$ ROBJ ON RCCOL.OBJ# = ROBJ.OBJ# LEFT JOIN SYS.ATTRCOL$ RACOL ON (RCCOL.OBJ# = RACOL.OBJ#) AND (RCCOL.INTCOL# = RACOL.INTCOL#) WHERE CONST.OWNER# = userenv('SCHEMAID') AND RCONST.OWNER# = userenv('SCHEMAID') AND CDEF.TYPE# = 4 /* 'R' Referential/Foreign Key */; 

Answer 6

如果您需要用户的所有外键，则使用以下脚本

 SELECT a.constraint_name, a.table_name, a.column_name, c.owner, c_pk.table_name r_table_name, b.column_name r_column_name FROM user_cons_columns a JOIN user_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name JOIN user_constraints c_pk ON c.r_owner = c_pk.owner AND c.r_constraint_name = c_pk.constraint_name JOIN user_cons_columns b ON C_PK.owner = b.owner AND C_PK.CONSTRAINT_NAME = b.constraint_name AND b.POSITION = a.POSITION WHERE c.constraint_type = 'R' 

基于Vincent Malgrat的代码

Answer 7

我知道现在回答迟了，但是让我回答，上面的一些答案是相当复杂的，因此这里要简单得多。

 SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name join all_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name WHERE c.constraint_type = 'R' AND a.table_name = 'your table name' 

Answer 8

如果想要从UAT环境表创buildFK约束到Live，则在dynamic查询下进行激活…..

  SELECT 'ALTER TABLE '||OBJ.NAME||' ADD CONSTRAINT '||CONST.NAME||' FOREIGN KEY ('||COALESCE(ACOL.NAME, COL.NAME)||') REFERENCES ' ||ROBJ.NAME ||' ('||COALESCE(RACOL.NAME, RCOL.NAME) ||');' FROM SYS.CON$ CONST INNER JOIN SYS.CDEF$ CDEF ON CDEF.CON# = CONST.CON# INNER JOIN SYS.CCOL$ CCOL ON CCOL.CON# = CONST.CON# INNER JOIN SYS.COL$ COL ON (CCOL.OBJ# = COL.OBJ#) AND (CCOL.INTCOL# = COL.INTCOL#) INNER JOIN SYS.OBJ$ OBJ ON CCOL.OBJ# = OBJ.OBJ# LEFT JOIN SYS.ATTRCOL$ ACOL ON (CCOL.OBJ# = ACOL.OBJ#) AND (CCOL.INTCOL# = ACOL.INTCOL#) INNER JOIN SYS.CON$ RCONST ON RCONST.CON# = CDEF.RCON# INNER JOIN SYS.CCOL$ RCCOL ON RCCOL.CON# = RCONST.CON# INNER JOIN SYS.COL$ RCOL ON (RCCOL.OBJ# = RCOL.OBJ#) AND (RCCOL.INTCOL# = RCOL.INTCOL#) INNER JOIN SYS.OBJ$ ROBJ ON RCCOL.OBJ# = ROBJ.OBJ# LEFT JOIN SYS.ATTRCOL$ RACOL ON (RCCOL.OBJ# = RACOL.OBJ#) AND (RCCOL.INTCOL# = RACOL.INTCOL#) WHERE CONST.OWNER# = userenv('SCHEMAID') AND RCONST.OWNER# = userenv('SCHEMAID') AND CDEF.TYPE# = 4 AND OBJ.NAME = <table_name>; 

Answer 9

 select d.table_name, d.constraint_name "Primary Constraint Name", b.constraint_name "Referenced Constraint Name" from user_constraints d, (select c.constraint_name, c.r_constraint_name, c.table_name from user_constraints c where table_name='EMPLOYEES' --your table name instead of EMPLOYEES and constraint_type='R') b where d.constraint_name=b.r_constraint_name 

Answer 10

 SELECT a.table_name, a.column_name, a.constraint_name, c.owner, -- referenced pk c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name JOIN all_constraints c_pk ON c.r_owner = c_pk.owner AND c.r_constraint_name = c_pk.constraint_name WHERE c.constraint_type = 'R' AND a.table_name :=TABLE_NAME AND c.owner :=OWNER_NAME; 

Answer 11

 WITH reference_view AS (SELECT a.owner, a.table_name, a.constraint_name, a.constraint_type, a.r_owner, a.r_constraint_name, b.column_name FROM dba_constraints a, dba_cons_columns b WHERE a.owner LIKE UPPER ('SYS') AND a.owner = b.owner AND a.constraint_name = b.constraint_name AND constraint_type = 'R'), constraint_view AS (SELECT a.owner a_owner, a.table_name, a.column_name, b.owner b_owner, b.constraint_name FROM dba_cons_columns a, dba_constraints b WHERE a.owner = b.owner AND a.constraint_name = b.constraint_name AND b.constraint_type = 'P' AND a.owner LIKE UPPER ('SYS') ) SELECT rv.table_name FK_Table , rv.column_name FK_Column , CV.table_name PK_Table , rv.column_name PK_Column , rv.r_constraint_name Constraint_Name FROM reference_view rv, constraint_view CV WHERE rv.r_constraint_name = CV.constraint_name AND rv.r_owner = CV.b_owner; 

Answer 12

对于Load UserTable（外键列表和它们引用的表）

 WITH reference_view AS (SELECT a.owner, a.table_name, a.constraint_name, a.constraint_type, a.r_owner, a.r_constraint_name, b.column_name FROM dba_constraints a, dba_cons_columns b WHERE a.owner = b.owner AND a.constraint_name = b.constraint_name AND constraint_type = 'R'), constraint_view AS (SELECT a.owner a_owner, a.table_name, a.column_name, b.owner b_owner, b.constraint_name FROM dba_cons_columns a, dba_constraints b WHERE a.owner = b.owner AND a.constraint_name = b.constraint_name AND b.constraint_type = 'P' ) , usertableviewlist AS ( select TABLE_NAME from user_tables ) SELECT rv.table_name FK_Table , rv.column_name FK_Column , CV.table_name PK_Table , rv.column_name PK_Column , rv.r_constraint_name Constraint_Name FROM reference_view rv, constraint_view CV , usertableviewlist UTable WHERE rv.r_constraint_name = CV.constraint_name AND rv.r_owner = CV.b_owner And UTable.TABLE_NAME = rv.table_name;